If you have a calculator with statistical functions, that's the way to go.
On my TI-83, I typed in invNorm(0.88) and got the result z = 1.17.
88% of the area under the normal curve is to the left of z = 1.17.
2(x+4)=18
2•x + 2•4 = 18
2x + 8 = 18
2x + 8 = 18
- 8 -8
_________
2x = 10
2x = 10
__ __
÷2 ÷2
x = 5
3,6,12,24,48,96,192,384,768,1536,3072,6144 all you have to do is multiply the last number by 2
If correct please mark Brainliest.
The vertex of the graph is (2,-4). It is a minimum as it is the lowest point on the parabola facing upwards. This would be option C.