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Temka [501]
3 years ago
15

Graph the equation to solve the system. y=2x+7 1/2y=x+7/2

Mathematics
1 answer:
vlabodo [156]3 years ago
3 0

Given equation is y=2x+7 and \frac{1}{2}y=x+\frac{7}{2}

Let's simplify the 2nd equation \frac{1}{2}y=x+\frac{7}{2} before we can start graph so that calculation will be easy

\frac{1}{2}y=x+\frac{7}{2}

multiply both sides by 2 to cancel out fractions

2*\frac{1}{2}y=2*x+2*\frac{7}{2}

y=2x+7

which is exactly same as the first equatoin so graph of both will be exactly same and solution will be infinitely many solutions.

y=2x+7 has y-intercept 7 so first point will be (0,7). Slope is 2 so rise 2 unit up then 1 right and graph the new point.


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Please help!!
ZanzabumX [31]

The two linear equations in two variable is:

12 x + 3 y = 40

7 x - 4 y = 38

(a) For a system of equations in two Variable

a x + by = c

p x + q y = r

It will have unique solution , when

\frac{a}{p}\neq \frac{b}{q}\neq\frac{c}{r}

As, you can see  that in the two equation Provided above

\frac{12}{7}\neq \frac{3}{-4}\neq \frac{40}{38}

So, we can say the system of equation given here has unique solution.

(b). If point (2.5, -3.4) satisfies both the equations, then it will be solution of the system of equation, otherwise not.

1. 12 x+3 y=40

2. 7 x-4 y=38

Substituting , x= 2.5 , and y= -3.4 in equation (1) and (2),

L.H.S of Equation (1)= 1 2 × 2.5 + 3 × (-3.4)

                             = 30 -10.20

                               = 19.80≠ R.H.S that is 40.

Similarly, L H S of equation (2)= 7 × (2.5) - 4 × (-3.4)

                                                  = 17.5 +13.6

                                                  = 31.1≠R HS that is 38

So, you can Write with 100 % confidence that point (2.5, -3.4) is not a solution of  this system of the equation.


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Step-by-step explanation:

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Equation of the line is,

x-4y = -12

8 0
3 years ago
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sveta [45]

Answer:

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