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seropon [69]
3 years ago
6

At what point do you feel it is necessary for environmentalists to get involved in creating man-made problems with natural ecolo

gical succession?
Biology
1 answer:
oksian1 [2.3K]3 years ago
6 0

Answer: Ecosystem degradation

Definition of terminologies:

1. Natural ecological succession is the gradual change in the species composition and diversity in the ecosystem and the development of ecosystem over a period of time, resulting to stable community.

2. Ecosystem refers to group of plants, animals and other living components functioning in their non-living environment.

3. Ecosystem degradation refers to the depletion of resources in the ecosystem

Explanation:

When there is ecosystem degradation, it is necessary for environmentalists to get involved in creating man-made problems with natural ecological succession and this process is called ecological restoration.

Environmentalists creates man-made problems to either accelerate or reverse the change in the ecosystem.

Degradation comes in different ways (e.g increased soil erosion/flooding, disease outbreak,deforestation, pollution of the ecosystem etc.) and are greatly influenced by climate change.

Environmentalists curb the menace by:

1. Introducing resistant species against disease outbreak;

2. Improved ecosystem service;

3. Buffer zone establishment to resist pollution in any form.

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The building blocks or monomers of nucleic acid molecules are called _____. See concept 5.5 (page 84) view available hint(s) the
Monica [59]

Answer;

-Nucleotides

Explanation;

-Nucleic acids are polynucleotides, that is, long chainlike molecules composed of a series of nearly identical building blocks called nucleotides. Each nucleotide consists of a nitrogen-containing aromatic base attached to a pentose (five-carbon) sugar, which is in turn attached to a phosphate group.

-A sugar-phosphate backbone joins together nucleotides in a DNA sequence. The sugar-phosphate backbone forms the structural framework of nucleic acids, including DNA and RNA. This backbone is composed of alternating sugar and phosphate groups, and defines directionality of the molecule.


7 0
3 years ago
Select ALL the correct answers.
tekilochka [14]

Answer:

(b) The interquartile range of B is greater than the interquartile range of A.

(d) The median of A is the same as the median of B.

Explanation:

Given

A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}

10th\ run = 9

So:

B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}

Required

Select all true statements

(a) & (d) Median Comparisons

A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}                         B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}

n = 9                                                         n = 10

Arrange the data:

A = \{1, 1, 1, 1, 2, 2,  2,3, 4\}               B = \{1,1,1,1,2,2,2,3,4,9\}

                               Median = \frac{n + 1}{2}th

Median = \frac{9 + 1}{2}th                            Median = \frac{10 + 1}{2}th

Median = \frac{10}{2}th                              Median = \frac{11}{2}th

Median = 5th                                 Median = 5.5}th --- average of 5th and 6th

Median = 2                                    Median = \frac{2+2}{2} = 2

Option (d) is correct because both have a median of: 2

(b) & (c) Interquartile Range Comparisons

A = \{1, 1, 1, 1, 2, 2,  2,3, 4\}               B = \{1,1,1,1,2,2,2,3,4,9\}

n = 9                                                         n = 10

First, calculate the lower quartile (Q1)

Q_1 = \frac{n + 1}{4}th[Odd n]             Q_1 = \frac{n}{4}th [Even n]

Q_1 = \frac{9 + 1}{4}th                            Q_1 = \frac{10}{4}th

Q_1 = \frac{10}{4}th                              Q_1 = 2.5

Q_1 = 2.5th                              

This means that:

Q_1 = 2nd + 0.5(3rd - 2nd)              Q_1 = 2nd + 0.5(3rd - 2nd)

Q_1 = 1 + 0.5(1- 1)                   Q_1 = 1+ 0.5(1 - 1)                      

Q_1 = 1                                       Q_1 = 1

Next, calculate the upper quartile (Q3)

Q_3 = \frac{3}{4}(n + 1)th [Odd n]             Q_3 = \frac{3}{4}(n)th [Even n]

Q_3 = \frac{3}{4}(9 + 1)th                            Q_3 = \frac{30}{4}th

Q_3 = \frac{30}{4}th                                     Q_3 = 7.5th  

Q_3 = 7.5th                                    

This means that:

Q_3 = 7th + 0.5(8th- 7th)           Q_3 = 7th + 0.5(8th- 7th)

Q_3 = 2 + 0.5(3- 2)                       Q_3 = 2+ 0.5(4 - 2)                      

Q_3 = 2.5                                       Q_3 = 3

The interquartile range is  IQR = Q_3 - Q_1

So, we have:

IQR = 2.5 - 1                  IQR = 3 - 1

IQR = 1.5                       IQR  =2

(b) is true because B has a greater IQR than A

(e) This is false because some spread measures (which include quartiles and the interquartile range) changed when the 10th data is included.

The upper quartile and the interquartile range of A and B are not equal

8 0
3 years ago
The various hormones secreted by the anterior pituitary that regulate the secretion of hormones from other endocrine organs are
Ksenya-84 [330]

Answer:

tropic hormones

Explanation:

Anterior pituitary is the anterior lobe  of the pituitary gland (hypophysis). It is also called the adenohypophysis. The secretions of the adenohypophysis are involved in the contol of many biological fuunctions: growth, stress, reproduction etc. Two major groups of hormones from the adenohypophysis are:

  1. Tropic hormones-regulate the secretion of hormones from other endocrine organs (Thyroid-stimulating hormone-TSH, Adrenocorticotropic hormone ACTH, Luteinizing hormone LH, Follicle-stimulating hormone-FSH)
  2. Trophic hormones-regulate the growth (TSH-stimulates the growth of thyroid gland  and ACTH which stimulates the growth of the adrenal cortex).
8 0
4 years ago
The plants in a red-tailed hawk’s food chain produce 3 million kcal of chemical energy per day. How much energy is available to
KATRIN_1 [288]

The amount of total energy at each trophic level decreases as it moves through, so 90% is lost at each level. This means that only 10 percent of the energy at any trophic level is transferred to the next level; and the rest is lost as heat.  

In this case, if a plant ecosystem has 3000000 kilocalories (kcal) of energy, about 300000 kcal will be transferred to primary consumers (for example grass hoppers). If the red-tailed hawks are tertiary consumers, they will get 3000 kcal of energy.


5 0
4 years ago
Can you please help me with this...
antiseptic1488 [7]

Answer:

A. Asexual

Explanation:

I majored in Biology

6 0
3 years ago
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