Answer:
the answer is 139 - c
Step-by-step explanation:
I did it on edge
Nah stop cheating in Fullard class smh:
Step-by-step explanation:
Answer:
The three consecutive odd integers are: -11, -13 and -15.
Step-by-step explanation:
Let the smallest number be represented by x. then the three consecutive odd integers are: x, (x + 2) and (x = 4).
The sum of the smallest number and twice the larges number = x + 2(x + 4)
Fifteen more than four times the middle number = 4(x + 2) + 15
So that;
x + 2(x + 4) = 4(x + 2) + 15
x + 2x + 8 = 4x + 8 + 15
3x + 8 = 4x + 23
3x - 4x = 23 - 8
-1x = 15
⇒ x = -15
(x + 2) = (-15 + 2) = -13
(x + 4) = (-15 + 4) = -11
The three consecutive odd integers are: -11, -13 and -15.
The function is already factored, so it equals zero if and only if one of its factors equals zero:
or
Since -2 is smaller than -3/2 the solutions are -2 and -3/2
4xy+8=36
-8 -8
4xy=28
\4 \4
xy=7
