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marin [14]
3 years ago
15

Express the radical using the imaginary unit, i.

Mathematics
1 answer:
MrMuchimi3 years ago
7 0

Answer:

±3i

Step-by-step explanation:

Given the value ±√-9, we are to express the value using the imaginary number 'I'

±√-9 = ±√9×-1

= ±√9 × √-1

In complex number, √-1 = i

The expression becomes;

±√9 = ±3 × i

±√9 = ±3i

Hence the value in simplified form is ±3i

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In triangle XYZ. the measurements of angle X and angle Y are 45° Which is the longest side of the triangle
ipn [44]

Answer:

the side XY

Step-by-step explanation:

we know 2 angles in a triangle. but are 45 degrees.

that means the third angle Z is 180-45-45 = 90 degrees.

the side opposite of the largest angle is the longest side.

opposite of Z is the side XY.

6 0
2 years ago
What is 5 1/2 +2 1/7 due in one hour help please
nika2105 [10]

Answer:

7 9/14

Step-by-step explanation:

1/2=7/14

1/7=2/14

7/14+2/14=9/14

5+2=7

6 0
2 years ago
Read 2 more answers
One side of a right triangle has a length of 12 feet. Which of the following could be lengths for the two other sides of the rig
Elodia [21]

Answer:

B

Step-by-step explanation:

Apply the Pythagorean Theorem to determine whether or not the given triplets represent right triangles or not:

I. 5 feet and 13 feet:  5^2 + 12^2 = 13^2 is TRUE

II.  9 ft and √63 ft:  9^2, 63, 12^2:  63 + 81 do add up to 144  TRUE

III.  2, 10, 12^2:  2 + 10 do NOT add up to 144.  FALSE

Answer B is correct

5 0
3 years ago
Write (1/3i)-(-6+2/3i) as a complex number in standard form
Eddi Din [679]

Answer:

6+\frac{i}{3}

Step-by-step explanation:

\frac{1}{3\imath}-(-6+\frac{2}{3\imath})

\frac{1}{3\imath}+6-\frac{2}{3\imath}

taking like terms together

\frac{1}{3\imath}-\frac{2}{3\imath}+6

taking LCM

\frac{1-2}{3\imath}+6

\frac{-1}{3\imath}+6

taking LCM

\frac{-1+18\imath}{3\imath}

splitting the term

\frac{-1+18\imath}{3\imath}

splitting the term

-\frac{1}{3\imath}+\frac{18\imath}{3\imath}

-\frac{1\times3\imath}{3\imath \times \imath}+6

-\frac{i}{3\imath^2}+6

we know that

\imath^2=-1

putting this value in above equation

\frac{\imath}{3}+6

7 0
3 years ago
HURRY PLZ!!!
nasty-shy [4]

Answer:

D) no solution

Step-by-step explanation:

1/ (x-2) + 1/(x+2) = 4/(x^2-4)

x cannot equal 2 or -2 since that would make our fractions equal 1/0 or be undefined

Factor the term on the right

1/ (x-2) + 1/(x+2) = 4/(x-2)(x+2)

Multiply both sides by (x-2) (x+2)

(x-2) (x+2) (1/ (x-2) + 1/(x+2)) = 4/(x-2)(x+2)*(x-2) (x+2)

Distribute

x+2 + (x-2) = 4

Combine like terms

2x = 4

Divide by 2

2x/2 = 4/2

x =2

But this is not a possible solution since that is not in the domain

6 0
3 years ago
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