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Zigmanuir [339]
3 years ago
5

5n+5=45 what does n =

Mathematics
1 answer:
joja [24]3 years ago
4 0
5n+5=45
Subtract 5 from both sides
5n=40
Divide both sides by 5
n=8

I hope this helps
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The vertex is (2, -3).
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If (x+2) is a factor of x^3-6x^2+kx+10, k=
Alja [10]
If a binomial (x-a) is a factor of a polynomial, then a is a root of this polynomial.

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3 0
3 years ago
!!Help!!<br>solve for x​
Murrr4er [49]

WXY = XYW ( = 41 ) ⇒  XYW is a isosceles triangle

⇒ XW = YW

⇒ 54 = 6x + 6

⇒ 6( x + 1 ) = 54

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⇒ x = 8

ok done. Thank to me :>

4 0
3 years ago
15. If x=a Sin2t (I+Cos2t) and y=b Cos 2t (1-Cos2t) then find<br>dy/dx at =22/7*4<br>​
Sav [38]

By the chain rule,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}

It looks like we're given

\begin{cases}x=a\sin(2t)(1+\cos(2t))\\y=b\cos(2t)(1-\cos(2t))\end{cases}

where <em>a</em> and <em>b</em> are presumably constant.

Recall that

\cos^2t=\dfrac{1+\cos(2t)}2

\sin^2t=\dfrac{1-\cos(2t)}2

so that

\begin{cases}x=2a\sin(2t)\cos^2t\\y=2b\cos(2t)\sin^2t\end{cases}

Then we have

\dfrac{\mathrm dx}{\mathrm dt}=4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t

\dfrac{\mathrm dy}{\mathrm dt}=-4b\sin(2t)\sin^2t+4b\cos(2t)\sin t\cos t

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{4b\cos(2t)\sin t\cos t-4b\sin(2t)\sin^2}{4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t}

\implies\boxed{\dfrac{\mathrm dy}{\mathrm dx}=\dfrac ba\tan t}

where the last reduction follows from dividing through everything by \cos(2t)\cos^2t and simplifying.

I'm not sure at which point you're supposed to evaluate the derivative (22/7*4, as in 88/7? or something else?), so I'll leave that to you.

8 0
3 years ago
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