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Zolol [24]
3 years ago
5

Thirty-two minus the product of 9 and a number is 140

Mathematics
1 answer:
solmaris [256]3 years ago
8 0
32-(9 x a)=140
32-9-a=140
23-a=140
-a=10-23
-a=-13
a=13

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Simplify 83. 24 192 512
loris [4]
83 is a prime 
24  = 2³x3
192 = 2⁶x3
256 = 2⁸ 
8 0
3 years ago
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Help please. Please gets this right.
Bas_tet [7]

Answer:

y=-3/2x

Step-by-step explanation:

4 0
3 years ago
-3(5)^2-(-2)(-8) simplify
avanturin [10]

To do this, we're going to use the order of operations (PEMDAS):

P - Parentheses

E - Exponents

M - Multiplication

D - Division

A - Addition

S - Subtraction

First let's do parentheses, there isn't anythig in parentheses we need to simplify, so we can skip this step.

Next let's look for exponents. I see we have a 5^2 so let's replace that with 5^2=25:

-3(25)-(-2)(-8)

Now let's look for multiplcation. We know that things that are right next to eachother in parentheses represent multiplcation, so let's simply this more:

-3(25)=-75

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And now we're left with a simple problem we know how to solve.

Answer: -91

Hope this helps!

3 0
3 years ago
Convert 3/5 into a percent
andrezito [222]
Divide it and get 0.6 then multiply by 100 so 60%
4 0
3 years ago
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A square is circumscribed about a circle with an 8-inch radius, as shown below. What is the area, in square inches, of the regio
sladkih [1.3K]

Answer:

Option 4. 256 - 64π is the correct option.

Step-by-step explanation:

In the given picture a square is circumscribed about a circle with a side = 2r

where r is the radius of the circle.

Therefore area of the square = (2r)² = 4r² = 4 × 8² = 4 × 64 = 256 in²

Now area of the circle = πr² = π × 8² = 64π in²

Now area of region that is inside the square and outside the circle =

Area of square - area of circle = (256 - 64π) in².

Therefore the answer is (256 - 64π).

8 0
3 years ago
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