Answer:
V = ∫∫∫rdrdθdz integrating from z = 2 to z = 4, r = 0 to √(16 - z²) and θ = 0 to 2π
Step-by-step explanation:
Since we have the radius of the sphere R = 4, we have R² = r² + z² where r = radius of cylinder in z-plane and z = height² of cylinder.
So, r = √(R² - z²)
r = √(4² - z²)
r = √(16 - z²)
Since the region is above the plane z = 2, we integrate z from z = 2 to z = R = 4
Our volume integral in cylindrical coordinates is thus
V = ∫∫∫rdrdθdz integrating from z = 2 to z = 4, r = 0 to √(16 - z²) and θ = 0 to 2π
Answer: 3.7 (to nearest tenth)
Working:
7/17 = x/9
63 = 17x
x = 63/17
x = 3.7 (to nearest tenth)
Answer:4.375
Step-by-step explanation:
A=-.25+6.7t, s=.75+4.5t when Amir catches up a=s so:
-.25+6.7t=.75+4.5t add .25 to both sides
6.7t=1+4.5t subtract 4.5t from both sides
2.2t=1 divide both sides by 2.2
t=10/22 hr
t≈0.45 hr (to nearest hundredth)
