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antiseptic1488 [7]
3 years ago
6

What is 2+5 (since this is very very hard its worth 20 points and I'll give brainliest to the first right answer)

Mathematics
2 answers:
Stolb23 [73]3 years ago
4 0
7 is the answer kskdidfifjfjfkfiff
Helga [31]3 years ago
4 0

Answer:

!!1

Step-by-step explanation:

2+5= 7!!

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On an alien planet with no atmosphere, acceleration due to gravity is given by g = 12m/s^2. A cannonball is launched from the or
almond37 [142]

Answer:

a) \vec r (t) = \left[(90\cdot \cos \theta)\cdot t \right]\cdot i + \left[(90\cdot \sin \theta)\cdot t -6\cdot t^{2} \right]\cdot j, b) \theta = \frac{\pi}{4}, c) y_{max} = 84.375\,m, t = 3.75\,s.

Step-by-step explanation:

a) The function in terms of time and the inital angle measured from the horizontal is:

\vec r (t) = [(v_{o}\cdot \cos \theta)\cdot t]\cdot i + \left[(v_{o}\cdot \sin \theta)\cdot t -\frac{1}{2}\cdot g \cdot t^{2} \right]\cdot j

The particular expression for the cannonball is:

\vec r (t) = \left[(90\cdot \cos \theta)\cdot t \right]\cdot i + \left[(90\cdot \sin \theta)\cdot t -6\cdot t^{2} \right]\cdot j

b) The components of the position of the cannonball before hitting the ground is:

x = (90\cdot \cos \theta)\cdot t

0 = 90\cdot \sin \theta - 6\cdot t

After a quick substitution and some algebraic and trigonometric handling, the following expression is found:

0 = 90\cdot \sin \theta - 6\cdot \left(\frac{x}{90\cdot \cos \theta}  \right)

0 = 8100\cdot \sin \theta \cdot \cos \theta - 6\cdot x

0 = 4050\cdot \sin 2\theta - 6\cdot x

6\cdot x = 4050\cdot \sin 2\theta

x = 675\cdot \sin 2\theta

The angle for a maximum horizontal distance is determined by deriving the function, equalizing the resulting formula to zero and finding the angle:

\frac{dx}{d\theta} = 1350\cdot \cos 2\theta

1350\cdot \cos 2\theta = 0

\cos 2\theta = 0

2\theta = \frac{\pi}{2}

\theta = \frac{\pi}{4}

Now, it is required to demonstrate that critical point leads to a maximum. The second derivative is:

\frac{d^{2}x}{d\theta^{2}} = -2700\cdot \sin 2\theta

\frac{d^{2}x}{d\theta^{2}} = -2700

Which demonstrates the existence of the maximum associated with the critical point found before.

c) The equation for the vertical component of position is:

y = 45\cdot t - 6\cdot t^{2}

The maximum height can be found by deriving the previous expression, which is equalized to zero and critical values are found afterwards:

\frac{dy}{dt} = 45 - 12\cdot t

45-12\cdot t = 0

t = \frac{45}{12}

t = 3.75\,s

Now, the second derivative is used to check if such solution leads to a maximum:

\frac{d^{2}y}{dt^{2}} = -12

Which demonstrates the assumption.

The maximum height reached by the cannonball is:

y_{max} = 45\cdot (3.75\,s)-6\cdot (3.75\,s)^{2}

y_{max} = 84.375\,m

7 0
3 years ago
What is:<br> m% of n?<br><br> PLEASE HELP ME
bija089 [108]

Answer:

<h3>m% of n</h3><h3>m/100 . n</h3>

<h3>mn/100</h3>

Step-by-step explanation:

<h3>I hope it helps ❤❤</h3>
8 0
2 years ago
I need help doing this.
Elanso [62]

a[n] = 7n - 16

The fifth term is a[5]

a[5] = 7(5) - 16 = 35 - 16  = 19

Answer: C. 19

3 0
3 years ago
Find the slope of the line represented by the table of values.
koban [17]
I dont know if im correct but i think its C
7 0
3 years ago
Factor completely<br><br> 8x^2-6x-2x^3
noname [10]

Answer:

2x(x-3)(-x+1)

Step-by-step explanation:

Factor 2x from everything -> 2x(4x-3-x^2)

Reorder the terms -> 2x(-x^2+4x-3)

Write 4x as a sum -> 2x(-x^2+3x+x-3)

Factor out -x from -x^2+3x looks like -> 2x(-x(x-3)+x-3)

Factor out x-3 from the expression -> 2x(x-3)(-x+1)

8 0
3 years ago
Read 2 more answers
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