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cluponka [151]
3 years ago
6

What is the range of values for the measurement 500 + or = 4%?

Mathematics
1 answer:
denis23 [38]3 years ago
4 0
The range of values is =5m^4/p that is your answer
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3x-2y=-5 and 4x+2y=-16​
podryga [215]

Answer:

x=-22/4

y=-3

Step-by-step explanation:

3x-2y=-5

4x+2y=-16

we <u>add</u> the equation

7y=-21

y=-3

then we find the x by taking a random equation

I take 4x+2y=-16

4x+2(-3)=-16

4x-6=-16

4x=-22

x=-22/4

7 0
3 years ago
Guys I need help plz! ( it would mean a lot if u help )
ExtremeBDS [4]

Answer:

━☆゚.*・。゚X>6

Step-by-step explanation:

Here,X is greater than 6

6 0
3 years ago
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What is the volume of a hemisphere that
ch4aika [34]

<u>Given</u>:

Given that the diameter of the hemisphere is 12.6 cm

The radius of the hemisphere is given by

r=\frac{d}{2}=\frac{12.6}{2}=6.3

We need to determine the volume of the hemisphere.

<u>Volume of the hemisphere:</u>

Let us determine the volume of the hemisphere.

The volume of the hemisphere can be determined using the formula,

V=\frac{2}{3} \pi r^3

Substituting the values, r = 6.3 and π = 3.14, we have;

V=\frac{2}{3} (3.14)(6.3)^3

Simplifying the values, we have;

V=\frac{2}{3} (3.14)(250.047)

V=\frac{1570.29516}{3}

Dividing, we have;

V=523.43172

Rounding off to the nearest tenth, we get;

V=523.4

Thus, the volume of the hemisphere is 523.5 cm³

6 0
3 years ago
Which equation can be simplified to find the inverse of y = 5x2 + 10?
zmey [24]

f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10

Step-by-step explanation:

interchanging the variables

x = 5y^2 + 10

5y^2 +10 = x

5y^2 = x - 10

dividing by 5

5y^2/5 = x/5 + -10/5

y^2 = x/5 + - 10/5

y^2 = x/5 - 2

y = 5 (x-10) 0/5 (sq.rt)

g(5x^2 + 10) = 5x/5

g(5x^2 + 10) = x

f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10

5 0
3 years ago
Read 2 more answers
What is the expression in radical form? (5ab)3/2
andrew11 [14]

It would be a  x/n = n      √a^x  

Hope this helps


8 0
3 years ago
Read 2 more answers
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