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Alexxandr [17]
4 years ago
14

Find the range of f(x)=

la1" title=" \sqrt{4 - x {?}^{2} } " alt=" \sqrt{4 - x {?}^{2} } " align="absmiddle" class="latex-formula">

​
Mathematics
1 answer:
balandron [24]4 years ago
4 0
The range would be y>=0 since the transformations did not affect the y values. If you want it in interval notation, it would be [0,infinity)
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nydimaria [60]

Answer:

(0,5), (1,3), (2,1)

Step-by-step explanation:

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3 years ago
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Find the value of x, given that all the segments that appear tangent are tangent.
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3 years ago
Max is observing the velocity of a runner at different times. After one hour, the velocity of the runner is 5 km/h. After two ho
Hatshy [7]
You only have two observations to work the equation for the velocity.

You only can assume a linear relation.

Part a.

Calling x the independent variable (time in hours) and y the dependent variable (velocity in km/h) =>

x (time in hours)         y (velocity in km/h)

1                                  5
2                                  3

Now you use the linear relation:

slope: (3 - 5) km/h/ (2 - 1)h = - 2 km/1h^2 = - 2 km/h ^2

Equation:

y - 3 = slope * (x - 2)

=> y - 3 = - 2 ( x - 2)

=> y - 3 = - 2x + 4

=> y = 3 - 2x + 4

=> y = - 2x + 7

that is the slope-intercept form.

the standard form is y + 2x - 7 = 0

part B.

to draw the graph you can make a table with the points for the first four hours:

x (time in hours)            y (velocity in km/h)
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1                                      -2(1) + 7 = 5

2                                      -2(2) + 7 = 3

3                                      -2(3) + 7 = 1

4                                     -2(4) + 7 = - 1

The graph, of course, is a straight line, because we started from that assumption.
7 0
4 years ago
A recent study stated that if a person chewed gum, the average number of sticks of gum he or she chewed daily was 8. Researcher
konstantin123 [22]

Answer:

The average number of sticks of gum a person chewed daily was greater than 8.

Step-by-step explanation:

We are given the following in the question:

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Sample mean, \bar{x} = 9

Sample size, n = 36

Alpha, α = 0.05

Population standard deviation, σ = 1

First, we design the null and the alternate hypothesis

H_{0}: \mu \leq 8\text{ gums}\\H_A: \mu > 8\text{ gums}

We use one-tailed z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{9 - 8}{\frac{1}{\sqrt{36}} } = 6

Now, z_{critical} \text{ at 0.05 level of significance } = 1.64

Since,  

z_{stat} > z_{critical}

We fail to accept the null hypothesis and reject the null hypothesis. We accept the alternate hypothesis.

Thus, the average number of sticks of gum a person chewed daily was greater than 8.

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4 years ago
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50. add all the sides and subtract 180 because it has to equal 180

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