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fgiga [73]
3 years ago
15

What is the value of X

Mathematics
2 answers:
poizon [28]3 years ago
5 0

<u>Answer:</u>

The value of x is 12 cm.

<u>Step-by-step explanation:</u>

From the given figure, we know that the two corresponding lines are parallel and so the two given triangles are congruent to each other.

Therefore, the corresponding sides of these triangles will also be proportional so we can write it as:

\frac{4}{4+16} =\frac{3}{3+x}

\frac{4}{20} =\frac{3}{3+x}

By cross multiplication:

12+4x=60

4x=60-12

4x=48

x=\frac{48}{4}

x=12

Therefore, the value of x is 12 cm.

alexdok [17]3 years ago
4 0

Answer:

x=12

Step-by-step explanation:

We have been given a graph of similar triangles. We are asked to find the value of x.

Since we know that corresponding sides of similar triangles are always in same proportion, so we will use proportions to find the length of x.

\frac{3}{x+3}=\frac{4}{16+4}

\frac{3}{x+3}=\frac{4}{20}

Upon cross multiplying our equation we will get,

4*(x+3)=3(20)

Upon distributing 4 we will get,

4x+12=60

Let us subtract 12 from both sides of our equation.

4x+12-12=60-12

4x=48  

Upon dividing both sides of our equation by 4 we will get,

\frac{4x}{4}=\frac{48}{4}  

x=12  

Therefore, the value of x will be 12.

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Step-by-step explanation:

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In which quadrant is (-1/2, -1.8)?
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X = -1/2 (negative)
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4 years ago
Differentiate Vx(x + 2) with respect to x.
Travka [436]

Answer:

y'= \frac{3x+2}{2\sqrt{x} }

General Formulas and Concepts:

<u>Calculus</u>

The derivative of a constant is equal to 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Product Rule: \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Chain Rule: \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

y=\sqrt{x} (x+2)

<u>Step 2: Rewrite</u>

y=x^{\frac{1}{2} } (x+2)

<u>Step 3: Differentiate</u>

  1. Product Rule [Basic Power/Chain Rule]:                 y'= \frac{1}{2} x^{\frac{1}{2} -1}(x+2)+x^{\frac{1}{2} }(1)
  2. Simplify:                                                                            y'= \frac{1}{2} x^{\frac{-1}{2}}(x+2)+x^{\frac{1}{2}}
  3. Rewrite:                                                                                        y'= \frac{x+2}{2\sqrt{x} } + \sqrt{x}
  4. Add:                                                                                                       y'= \frac{3x+2}{2\sqrt{x} }
7 0
3 years ago
Can someone tell me how to approach this, I could care less about the answer I just want to know how to solve this without Desmo
kipiarov [429]

Answer:

the vertex is at (4, -14)

Step-by-step explanation:

Review "quadratic equations."  These have three terms, and the highest power of x is x^2.  We need to identify the coefficients of the x^2, x and x^0 terms to get info needed to identify the axis of symmetry.

Given f(x) = x^2 - 8x + 2, we see that these coefficients are 1, -8 and 2.

                                                                            b

The formula for the axis of symmetry is x  = - ------

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which here is x = -(-8)/[2*1], or x = 8/2  or x = 4:  the axis of symmetry.

To find the y-coordinate of the vertex, evaluate the function at x = 4:

f(4) = 4^2 - 8(4) + 2 = 16 - 32 + 2, or f(4) = -14.

Thus, the vertex is at (4, -14).  The graph is that of a parabola that opens up, and the parabola is symmetric about the vertical line x = 4.

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mestny [16]

Answer:

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Step-by-step explanation:

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