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3 years ago

The set of whole numbers is not a subset OF --

Mathematics

1 answer:

AlekseyPX3 years ago

7 0

I think the answer is b.integers. Hope this helps. :)

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What’s the answer too h(x) = 17 + x/6

mixer [17]

-102 = x

H(x)=17+x/6
0=17+x/6
6x17
0=102+x
-x=102
X=-102

3 0

3 years ago

Distance the points Q(-1,-7) and H(-4,1) in coordinate plane

Airida [17]

Answer:

hope you know Distance formula

Step-by-step explanation:

Think the answer is

$\sqrt{73}$

units

4 0

2 years ago

ANYONE ON BRAIN PLS HELP ME.

miv72 [106K]

Answer:

30420ft

Step-by-step explanation:

We have to break the shape into two. So..

13 times 26=338

now the top..23-13=10

10 times 9 = 90

338 times 90 = 30420 ft

8 0

2 years ago

Solve |-3d | =15 please lol

Keith_Richards [23]

Answer:

$d=-5 \text{ or } d=5$

Step-by-step explanation:

$|-3d|=15\\\\-3d=15 \text{ or } -3d=15\\\\\frac{-3d=15 \text{ or } -3d=15}{-3}\\\\\boxed{d=-5 \text{ or } d=5}$

Hope this helps.

7 0

3 years ago

Sadiq measured the dimensions of a 1 kg bag of sugar and found the length was 9.2 cm, the width was 6 cm and the height was 14.1

garik1379 [7]

Answer:

$d=1.28\times 10^{-6}\ g/cm^3$

Step-by-step explanation:

The mass of a bag of sugar, m = 1 kg = 0.001 g

Length of bag, l = 9.2 cm

Width of bag, b = 6 cm

Height of the bag, h = 14.1 cm

We need to find the density of the sugar bag.

Density = mass/volume

So,

$d=\dfrac{0.001\ g}{9.2\times 6\times 14.1\ cm^3}\\\\d=1.28\times 10^{-6}\ g/cm^3$

So, the density of the bag is $1.28\times 10^{-6}\ g/cm^3$ .

7 0

2 years ago