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o-na [289]
3 years ago
12

The set of whole numbers is not a subset OF --

Mathematics
1 answer:
AlekseyPX3 years ago
7 0
I think the answer is b.integers. Hope this helps. :)
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Answer:good for him

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Help me please this is due today :((<br> Show all work for it pleaseee
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Length C, B= 90 mi

Step-by-step explanation:

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<em>Hope it helps!!</em>

5 0
2 years ago
What is the MAD of the numbers (Round to the nearest tenth.)<br><br> 9,7,6,8,6,6
uranmaximum [27]

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Step-by-step explanation:

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6 0
3 years ago
One number is 6 more than twice the other number. If the sum of the two numbers is ​21, find the two numbers
hichkok12 [17]

Answer:

One number, let's call it x, is 6 more than twice the other number, let's say this number is y.

x= 2y+6

x+y=21

We're left with a system of equations.

If we substitute the first equation in the second we find the value of y.

(2y+6)+y=21

3y+6=21

3y=15

<u><em>y=5</em></u>

Now that we have found the value of y, we can take that value and substitute it in the second equation (since it's easier) to find the value of x.

x+ (5)=21

<u><em>x=16</em></u>

<u><em>Now to check if our answers are correct, we plug in both values into any equation and see if they equate.</em></u>

x+y=21

(16)+(5)=21

21=21

Our solution is correct!

4 0
2 years ago
Please please help 100 points
stiks02 [169]

We're given

\displaystyle \int_4^{-10} g(x) \, dx = -3

which immediately tells us that

\displaystyle \int_{-10}^4 g(x) \, dx = 3

In other words, swapping the limits of the integral negates its value.

Also,

\displaystyle \int_4^6 g(x) \, dx = 5

The integral we want to compute is

\displaystyle \int_{-10}^6 g(x) \, dx

which we can do by splitting up the integral at x = 4 and using the known values above. Then the integral we want is

\displaystyle \int_{-10}^6 g(x) \, dx = \int_{-10}^4 g(x) \, dx + \int_4^6 g(x) \, dx = 3 + 5 = \boxed{8}

7 0
2 years ago
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