Answer:
Well your answer is yes, and you shouldn't be calling yourself d u m b
Step-by-step explanation:
(By the way, I would love Brainliest! :)
A_n= a₁+(n-1)d
a₁ first term
n terms
d distance between each value
a_n= 12+(405-1)(5)=2032
Answer:
5.714 liters of the 5% solution and 4.286 of the 40%.
Step-by-step explanation:
Let x be the volume of 40% solution and y = volume of the 5% solution.
x + y = 10
0.40x + 0.05y = 0.20(x + y)
From the first equation x = 10 -y so we have:
0.40(10 - y) + 0.05y = 0.20( 10 - y + y)
4 - 0.40y + 0.05y = 2
-0.35y = -2
y = 5.714 liters of the 5%.
and x = 10 - 5.714 = 4.286 liters of the 40% solution.
Step-by-step explanation:
If Ken wants to pay more than 130, he needs to drive more than 90 miles. You subtract 94 from 130, which equals 36. 36 divided by .4 (for the price per mile) and it equals 90.
Answer:
<em>793 food hampers were distributed</em>
Step-by-step explanation:
We need to find how many food hampers were distributed in a typical week, knowing that
- 200 hampers were distributed on Mondays
40 fewer hampers were distributed on Tuesdays than on Mondays, thus:
- 160 hampers were distributed on Tuesdays
on Wednesdays, the volume is 1.3 times Tuesday’s volume, thus 160*1.3=
- 208 hampers were distributed on Wednesdays
on Thursdays the number of hampers distributed was 3/4 of Monday’s volume, thus 3/4*200=
- 150 hampers were distributed on Thursdays
on Fridays, 50% of Thursday’s volume was distributed, therefore 50%*150=
- 75 hampers were distributed on Fridays
The total number of food hampers distributed in the week is
200+160+208+150+75=793
793 food hampers were distributed