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Papessa [141]
3 years ago
14

bobby pays a $25 membership free to join YMCA gym. This gym allows members to attend any exercise class for only $4. The linear

equation can be written as T=4c + 25, where T represents the total cost of classes and the gym membership fee. Let c represent the number of classes bobby attended. find the cost, T, when bobby went to 2,4,8, and 10 classes.
Mathematics
1 answer:
blagie [28]3 years ago
7 0

Answer:

Step-by-step explanation:

T = 4c + 25....where c = # of classes and T = total cost

2 classes...so sub in 2 for c and solve for T

T = 4(2) + 25

T = 8 + 25

T = 33 <==== with 2 classes ,its $ 33

4 classes....so sub in 4 for c and solve for T

T = 4(4) + 25

T = 16 + 25

T = 41 <==== with 4 classes, its $ 41

8 classes....sub in 8 for c

T = 4(8) + 25

T = 32 + 25

T = $ 57 <==== with 8 classes, its $ 57

10 classes...sub in 10 for c

T = 4(10) + 25

T = 40 + 25

T = 65 <===== with 10 classes, its $ 65

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valina [46]

Answer: 9/12, 2/12

Step-by-step explanation:

Start by writing multiples of 6 and 4

4: 4, 8, 12

6: 6, 12, 18

Did you see the multiple that both numbers have? Yup, it's 12. So that has to be your denominator for both fractions. This is because you have to have the <u>LEAST</u> COMMON Denominator (LCD). So both numbers have 12 in common as one of their multiples and, it's the least common one because there are no numbers that come before it that are common for both numbers. Now, you just have to change the denominators of both fractions into 12. To do that to 3/4, just multiply the top and bottom by 3 to get 9/12. To do that to 1/6, just multiply the top and bottom by 2 to get 2/12.  Hope this helps!

NOTE: REMEBER THAT WHATEVER YOU DO TO THE TOP OF A FRACTION, YOU HAVE TO DO IT TO THE BOTTOM TOO (AND VICE VERSA)

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3 years ago
Use the quadratic formula to solve 2x^2 + 2x - 12?
Firdavs [7]

Answer:

Step-by-step explanation:

(x+2)(x-3)

8 0
3 years ago
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4 0
3 years ago
While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
3 years ago
3h-k=10<br>h-k=2<br>can u guys please help me
katen-ka-za [31]
Hi, hope this helps :)

8 0
3 years ago
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