<span> y^2 = (3x + 1)^3 / 9x + 2
2*y*(dy/dx)=(9</span>(3x + 1)^2*(9x + 2) -((9*(3x + 1)^3))/ ((9x + 2)^2)
(dy/dx)=(9(3x + 1)^2*(9x + 2) -((9*(3x + 1)^3))/ (2*y*(9x + 2)^2)
(dy/dx)=(9(3x + 1)^2*(6x + 1))/ (2*y*(9x + 2)^2)
answer
A
for the first truck 1680 / 14 = 120 liters used
the second 1680 / 12 = 140 litres used
so 140-120 = 20 liters <span>the second truck used more </span>
Answer:
y=1; x=2
Step-by-step explanation:
Substitution:
x=2y
2x+5y=9
=> if x=2y, plug in the x value into other equation, so
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2(2y)+5y=9
4y+5y=9
9y=9
y=1
You have the Y value, so now solve for X
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plug in y value to x=2y
so x=2(1)
x=2
Answer:
B
Step-by-step explanation:
Distributing the right side, the equation becomes
6-x=16+4x
Add x to both sides and subract 16
5x=-10
Divide by 5
x=-2
2 3/4 hours is 165 minutes
1hr and 55 min is 115 minutes
So 2 3/4 hours is 50minutes longer than 1hr and 55 min.