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3 years ago

Help with this problem

Mathematics

1 answer:

natita [175]3 years ago

3 0

Y = 6x - 4

basically, we just sub answer choices in to see which ones make the equation true.

answer is : (0,-4) , (1,2) , (3,14)

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Which input value produces the same output value for

Natali5045456 [20]

Answer:

x=1

Step-by-step explanation:

it is the point of intersection of both lines which (1,1)

for x=1 both produce same value i.e.,1

7 0

3 years ago

Philip is conducting a survey to determine the weight of 100 cows on a farm. Which of the following questions is an appropriate

liubo4ka [24]

Because Philip is conducting a survey that pertains to the weight of the cows, he needs statistics that directly relate to weight.

The cows being overweight doesn't give Philip concrete information on the weight of the cows, as it doesn't give the amount of pounds a cow weighs. Average age has nothing to do with weight, and normal body weight doesn't give concrete information on weight.

The answer is "<span>What is the weight of each cow on the farm?".</span>

5 0

3 years ago

Read 2 more answers

Find the slope and y-intercept of the line through the points (-3,-4) and (0,-1)

Alja [10]

Answer:

Slope=1, y-intercept=-1.

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-1-(-4))/(0-(-3))

m=(-1+4)/(0+3)

m=3/3

m=1

y-(-4)=1(x-(-3))

y+4=x+3

y=x+3-4

y=x-1

y=mx+b where m=slope and b=y-intercept

so you have slope of 1 and y-intercept of -1

6 0

3 years ago

A jeweler wants to make 14 grams of an alloy that is precisely 75% gold.. The jeweler has alloys that are 25% gold, 50% gold, &a

Goryan [66]

Given that the jeweler has alloys that are 25% gold, 50% gold, and 82% gold.

As he wants to make 14 grams of an alloy by adding two different alloys that is precisely 75% gold, so one alloy must have a percentage of gold more than 75%.

One alloy is 82% gold and, the second can be chosen between 25% gold, 50% gold, so there are two cases.

Case 1: 82% gold + 50% gold

Let x grams of 82% gold and y grams of 50% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 50% of y

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times y \\\\$

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times (14-x)$ [as x+y=14]

$\Rightarrow 75 \times 14 = 82 \times x + 50 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 50 \times14-50\times x \\\\\Rightarrow 75 \times 14 = 32 \times x + 50 \times14 \\\\\Rightarrow 32 \times x =75 \times 14 - 50 \times14 \\\\$

$\Rightarrow x =(25 \times 14)/32=10.9375$ grams

and $y = 14-x= 14-10.9375=3.0625$ grams.

Hence, 10.9375 grams of 82% gold and 3.0625 grams of 50% gold added to make 14 grams of 75% gold.

Case 2: 82% gold + 25% gold

Let x grams of 82% gold and y grams of 25% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 25% of y

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times y \\\\\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times (14-x) \\\\ \Rightarrow 75 \times 14 = 82 \times x + 25 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 25 \times14-25\times x \\\\\Rightarrow 75 \times 14 = 57 \times x + 25 \times14 \\\\\Rightarrow 57 \times x =75 \times 14 - 25 \times14 \\\\$

$\Rightarrow x =(50 \times 14)/57=12.28$ grams

and $y = 14-x= 14-12.28=1.72$ grams.

Hence, 12.28 grams of 82% gold and 1.72 grams of 50% gold added to make 14 grams of 75% gold.

3 0

2 years ago

Find the slope of 10y = 7x + 5.<br> Round to the third.

hram777 [196]

Answer:

0.7

Step-by-step explanation:

10y = 7x + 5

Divide both sides by 10.

y = 7x/10 + 5/10

y = 0.7x + 0.5

On a straight line of the form y = kx + m, k is the slope of the line.

In our line, y = 0.7x + 0.5, k is 0.7. Thus, the slope of our function is 0.7

Answer: 0.7

8 0

3 years ago