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Vika [28.1K]
3 years ago
14

|x| + |y| Evaluate the expression if x = 16 and y = 13.

Mathematics
2 answers:
Schach [20]3 years ago
8 0

Answer:

|x| + |y| = 29

Step-by-step explanation:

We have been given the expression;

|x| + |y|

We are required to evaluate the above expression if;

x = 16 and y = 13

The parallel vertical lines imply that we are dealing with the absolute value of x and y;

|x| + |y| = |16| + |13|

           = 16 + 13

           = 29

Ede4ka [16]3 years ago
4 0

Answer:

The correct answer is 29

Step-by-step explanation:

<u>Points to remember</u>

|x| = x

|-x| = x

It is given an expression, |x| + |y|

<u>To find the value of given expression</u>

|x| + |y|  if x = 16 and y = 13

Substitute the value of x and y in the above expression,

|x| + |y| = |16| + |13|

 = 16 + 13 = 29

Therefore the correct answer is 29

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3 years ago
A survey of 1,562 randomly selected adults showed that 522 of them have heard of a new electronic reader. The accompanying techn
tester [92]

Answer:

a) We want to test the claim that 35​% of adults have heard of the new electronic reader, then the system of hypothesis are.:  

Null hypothesis:p=0.35  

Alternative hypothesis:p \neq 0.35  

And is a two tailed test

b) z=\frac{0.334 -0.35}{\sqrt{\frac{0.35(1-0.35)}{1562}}}=-1.326  

c) p_v =2*P(z  

d) Null hypothesis:p=0.35  

e) Fail to reject the null hypothesis because the P-value is greater than the significance level, alpha.

Step-by-step explanation:

Information provided

n=1562 represent the random sample selected

X=522 represent the people who have heard of a new electronic reader

\hat p=\frac{522}{1562}=0.334 estimated proportion of people who have heard of a new electronic reader

p_o=0.35 is the value to verify

\alpha=0.05 represent the significance level

z would represent the statistic

p_v represent the p value

Part a

We want to test the claim that 35​% of adults have heard of the new electronic reader, then the system of hypothesis are.:  

Null hypothesis:p=0.35  

Alternative hypothesis:p \neq 0.35  

And is a two tailed test

Part b

The statistic for this case is given :

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.334 -0.35}{\sqrt{\frac{0.35(1-0.35)}{1562}}}=-1.326  

Part c

We can calculate the p value using the laternative hypothesis with the following probability:

p_v =2*P(z  

Part d

The null hypothesis for this case would be:

Null hypothesis:p=0.35  

Part e

The best conclusion for this case would be:

Fail to reject the null hypothesis because the P-value is greater than the significance level, alpha.

5 0
3 years ago
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