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3 years ago

|x| + |y| Evaluate the expression if x = 16 and y = 13.

Mathematics

2 answers:

Schach [20]3 years ago

8 0

Answer:

|x| + |y| = 29

Step-by-step explanation:

We have been given the expression;

|x| + |y|

We are required to evaluate the above expression if;

x = 16 and y = 13

The parallel vertical lines imply that we are dealing with the absolute value of x and y;

|x| + |y| = |16| + |13|

= 16 + 13

= 29

Ede4ka [16]3 years ago

4 0

Answer:

The correct answer is 29

Step-by-step explanation:

<u>Points to remember</u>

|x| = x

|-x| = x

It is given an expression, |x| + |y|

<u>To find the value of given expression</u>

|x| + |y| if x = 16 and y = 13

Substitute the value of x and y in the above expression,

|x| + |y| = |16| + |13|

= 16 + 13 = 29

Therefore the correct answer is 29

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Kevin is 3 years older than Daniel. Two years ago, Kevin was 4 times as old as Daniel. How old is Daniel now?

Radda [10]

Answer:

Kevin is 6 years old and Daniel is 3 years old

Step-by-step explanation:

They are now 3 years apart but two years ago, they were 4 and 1 years old, so Kevin was 4 times older than.

Hope this helped :)

5 0

3 years ago

PLEASE HELP ME:<br><br> Find the perimeter of the figure. Round to the nearest tenth.

Ksenya-84 [330]

Answer:

perimeter = 20.9 units

Step-by-step explanation:

perimeter

perimeter = distance around two dimensional shape

= addition of all sides lengths

<h2>perimeter of the figure</h2><h2>= AB+BC+CD+AD</h2>

distance formula:

$d = \sqrt{( x_{2} - x_{1}) {}^{2} + ( y_{2} - y_{1}) {}^{2} }$

<h3>1) distance of AB</h3>

A(-3,0) B(2,4)

x1 = -3 x2 = 2

y1 = 0 y2 = 4

(substitute the values into the distance formula)

$ab = \sqrt{(2 - ( - 3)) {}^{2} + (4 - 0) {}^{2} }$

$ab = \sqrt{5 {}^{2} + 4 {}^{2} }$

$ab = \sqrt{41}$ AB = 6.4 units

<h3>2) distance of BC</h3>

B(2,4) C(3,1)

x1 = 2 x2 = 3

y1 = 4 y2 = 1

$bc = \sqrt{(3 - 2) {}^{2} + (1 - 4) {}^{2} }$

$bc = \sqrt{1 {}^{2} + ( - 3) {}^{2} }$

$bc = \sqrt{10}$

BC = 3.2 units

<h3>3) distance of CD</h3>

C(3,1) D(-4,-3)

x1 = 3 x2 = -4

y1 = 1 y2 = -3

$cd = \sqrt{( - 4 - 3) {}^{2} + ( - 3 - 1)) {}^{2} }$

$cd = \sqrt{( - 7) {}^{2} + ( - 4 ){}^{2} }$

$cd = \sqrt{65}$

CD = 8.1 units

<h3>4) distance of AD</h3>

A(-3,0) D(-4,-3)

x1 = -3 x2 = -4

y1 = 0 y2 = -3

$ad = \sqrt{( - 4 - ( - 3)) {}^{2} + ( - 3 - 0) {}^{2} }$

$ad = \sqrt{( - 1) {}^{2} + ( - 3) {}^{2} }$

$ad = \sqrt{10}$

AD = 3.2 units

<h2>perimeter of figure</h2>

= AB+BC+CD+AD

= 6.4 + 3.2 + 8.1 + 3.2

= 20.9 units

8 0

3 years ago

In the coordinate plane, draw quadrilateral ABCD with A(–5, 0), B(2, –6), C(8, 1), and D(1, 7), then demonstrate that ABCD is a

Len [333]

Answer:

ABCD is a rectangle

Step-by-step explanation:

∵ A = (-5 , 0) , B = (2 , -6) , C = (8 , 1) , D = (1 , 7)

∵ The x-coordinate of the mid-point of AC = (-5 + 8)/2 =3/2

∵ The y-coordinate of the mid-point of AC = (0 + 1)/2 = 1/2

∴ The mid-point of AC = (3/2 , 1/2)

∵ The x-coordinate of the mid-point of BD = (2 + 1)/2 =3/2

∵ The y-coordinate of the mid-point of BD = (-6 + 7)/2 = 1/2

∴ The mid-point of BD = (3/2 , 1/2)

∴ The mid-point of AC = The mid-point of BD ⇒ (1)

∵ AC = √[(8 - -5)²+(1 - 0)² = √170

∵ BD = √[(1 - 2)²+(7 - -6)² = √170

∴ AC = BD ⇒ (2)

From (1) and (2)

AC and BD equal each other and bisects each other

∴ ABCD is a rectangle

7 0

3 years ago

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tatuchka [14]

Answer:

Step-by-step explanation:

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5 0

3 years ago

Multiply. Write in simplest form. 1/2 * 24

Dennis_Churaev [7]

Answer:

1. 12

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3. 6.8

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Step-by-step explanation:

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3 years ago