(7x + 4)(7x + 4) and (x – 9)(x – 9) are Perfect square trinomial. (5x + 3)(5x – 3) and (–3x – 6)(–3x + 6) shows the Difference of squares.
<h3>What is a perfect square?</h3>
A perfect square is a number system that can be expressed as the
square of a given number from the same system.
The following are the answers
(5x + 3)(5x – 3) Difference of squares
(7x + 4)(7x + 4) is a Perfect square trinomial
(2x + 1)(x + 2) has Neither a difference of squares nor a perfect square trinomial.
(4x – 6)(x + 8) has Neither a difference of squares nor a perfect square trinomial.
(x – 9)(x – 9) is Perfect square trinomial
(–3x – 6)(–3x + 6) = 
Difference of squares.
Learn more about perfect square:
brainly.com/question/1415730
Answer:
follow the steps bellow
Step-by-step explanation:
since you already have the x values it is easier,once you have the the y values you are going to plot the point the left side of the table are the x values and the right side are the y values. X values on a graph is the horizontal line or the line that goes left to right, and the y values on the graph re the line that goes vertical or up and down.
Answer:
Step-by-step explanation:
Area of an equilateral triangle = 
Sub in your value of 16ft
A = 
A = 110.85 
Answer:
1. ΔXYZ is a right Δ with altitude YU.
Given
2. ΔXYZ ~ ΔYUZ
Right Triangle Altitude Similarity Theorem
3. VW || XY
Given
4. ∠VWZ ≅ ∠XYZ
Corresponding angles
5. ∠Z ≅ ∠Z
Reflexive property of congruence
6. ΔXYZ ~ ΔVWZ
AA Similarity postulate
7. ΔYUZ ~ ΔVWZ
Transitive property of similar triangles
Step-by-step explanation:
The first statement is given in the problem. Since we know the altitude of a right triangle, we can use the Right Triangle Altitude Similarity Theorem to say that the triangles formed by the altitude are similar to each other and the original triangle.
Next, we are given in the problem statement that the lines VW and XY are parallel. Therefore, ∠VWZ and ∠XYZ are corresponding angles, which makes them congruent. And since ∠Z is equal to itself (by reflexive property), we can use AA similarity to say ΔXYZ and ΔVWZ are similar.
Finally, combining statements 2 and 6, we can use transitive property to say that ΔYUZ and ΔVWZ are similar.
