9514 1404 393
Answer:
6. step 2; terms are improperly combined; it should be -61n-8=-8
7. no; point (2, 5) is not part of the solution in the left graph
Step-by-step explanation:
6. Step 2 should be ...
-61n -8 = -8 . . . . . because -5n-56n = -61n, not -51n
__
7. The boundary lines of both graphs go through the point (2, 5). In the left graph, the line is dashed, indicating that points on the line are not part of the solution set. The point (2, 5) on the dashed line is not a solution to that inequality.
The solid boundary line indicates that the points on the line are part of the solution set. The point (2, 5) on the solid line is a solution to that inequality.
The point (2, 5) is not a solution to both inequalities.
Answer:
Heyy
Step-by-step explanation:
△ABC is a right angled triangle and right angle at B
sinA=
AC
BC
, cosA=
AC
AB
⟹sinA+cosA=
AC
BC
+
AC
AB
=
AC
BC+AB
[We know that sum of two sides of a triangle is greater than the third side]
⟹sinA+cosA>
AC
AC
=1
Hence, sinA+cosA>1
The answer is 3, since 3*3*3 equals 27
8 and 1
8 squared is 64 and 1 squared is 1
64 + 1 = 65
Hope this helps :)
