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Bess [88]
3 years ago
14

Simply this question and get marked branlist

Mathematics
1 answer:
Liula [17]3 years ago
4 0

Answer:

13) 16d^8c^8

Other) 72n^-5r^-1

Step-by-step explanation:

13) 2x8=16

d^3*d^5=d^8

c^6*c^2=c^8

16d^8c^8

Other problem: (hard to read, so check my numbers)

8x9=72

n*n^-6=n^-5

r^-4*r^3=r^-1

72n^-5r^-1

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A concession stand sells hamburgers (h) for $2 and hotdogs (d) for $1. On Friday night they sold a total of 300 hamburgers and h
kenny6666 [7]
420 / 2 = 210
210 / h = 105
210 / d = 210

h = 2
d = 1

they selled 105 burgers and 210 hot dogs. hope i helped ;)
8 0
3 years ago
What is this answer.
Ronch [10]

Answer:

the third one

Step-by-step explanation:

3 0
4 years ago
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Can someone please tell me if it's A, B, C or D
Y_Kistochka [10]
-1 is greater then 1.05 then 1.05 then 1.55
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8 0
3 years ago
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A total of 626 tickets were sold for the school play. They were either adult tickets or student tickets. There were 74 fewer stu
Sholpan [36]

Answer:

351 adults and 275 students

Step-by-step explanation:

We can set-up a system of equations to find the number of adults. We know students and adults attended. We will let s be the number of students and a be the number of adults. Since 626 tickets were purchased, then s+a=626.

We also know that 74 fewer student tickets then adult tickets. So s+76=a, the number of student tickets plus 76 will be the number of adult tickets.

We will solve by substituting one equation into the other. We substitute a=76+s into s+a=626. Simplify and isolate the variable a.

s+a=626

s+76+s=626

2s+76=626

2s+76-76=626-76

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s=275

This means that 275 students attended and 351 adults attended since 275+351=626.


6 0
4 years ago
How many real-number solutions does the equation have?
Alexxx [7]
I believe the correct answer would be that it has one solution which is 5. Calculating x for the quadratic equation, you will only get one value so it should be one solution. Hope this answers the question. Have a nice day.
8 0
3 years ago
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