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timurjin [86]
3 years ago
15

If –3 + i is a root of the polynomial function f(x), which of the following must also be a root of f(x)?

Mathematics
1 answer:
irina1246 [14]3 years ago
7 0

Answer:

Step-by-step explanation:

REcall that f(x) is a polynomial whose one of its roots is -3+i. The fundamental algebra theorem states that any polynomial of degree n has n complex roots. In the real case, it can be also interpreted as any polynomial can be factored in factors of degree at most 2.

Consider that given a polynomial of degree 2 of the form ax^2+bx+c the solutions are given by

x = \frac{-b \pm \sqrt[]{b^2-4ac}}{2a}

In this case, the fact that x is real or complex depends on the number b^2-4ac which is called the discriminant. When this number is negative, we have that x is a complex root. Let say that b^4-4ac and that \sqrt[]{b^4-4ac}=di, so the roots are given by

x_1 = \frac{-b + di}{2a}, x_2 = x_1 = \frac{-b - di}{2a}

this means that, whenever we have a complex root, the other root is the complex conjugate. Recall that the complex conjugate of a complex number of the form a+bi is obtained by changing the sign of the imaginary part, that is a-bi.

So, in our case since -3+i is a root, then -3-i necessarily is another root.

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My pigg y bank has only pennies and nicklels in it , and 2/7 of the coins are nickel If i remove 84 pennies then 1/3 of the reme
zubka84 [21]

Answer:

There are 105 pennies in the piggy bank.

There are 42 nickels in the piggy bank.

Step-by-step explanation:

there are:

p pennies in the piggy bank

n nickels in the piggy bank

Then we can define T, the total number of coins, as:

T = p + n

We know that 2/7 of the total number of coins are nickels.

This can be written as:

n = (2/7)*T = (2/7)*(n + p)

And if we remove 84 pennies, 1/3 of the remaining coins are pennies.

This can be written as:

p - 84 = (1/3)*(n + p - 84)

Then we have a system of two equations:

n = (2/7)*(n + p)

p - 84 = (1/3)*(n + p - 84)

Let's solve the system, to do it, we first need to isolate one of the variables in one of the equations.

We can isolate n in the first one, to get:

n = (2/7)*(n + p) = (2/7)*n + (2/7)*p

n - (2/7)*n = (2/7)*p

n*(5/7) = (2/7)*p

n = (7/5)*(2/7)*p = (2/5)*p

n = (2/5)*p

Now we can replace this in the other equation:

p - 84 = (1/3)*(n + p - 84)

p - 84 = (1/3)*( (2/5)*p + p - 84)

Let's solve this for p

p - 84 = (1/3)*( (7/5)*p - 84)

3*(p - 84) = (7/5)*p - 84

3p - 252 = (7/5)*p - 84

3*p - (7/5)*p = 252 - 84

(15/5)*p - (7/5)*p = 168

(8/5)*p = 168

p = (5/8)*168 = 105

There are 105 pennies in the piggy bank.

And we know that:

n = (2/5)*p = (2/5)*105 = 42

There are 42 nickels in the piggy bank.

4 0
3 years ago
Solve by substitution. Show each step of your work.
zaharov [31]

5x + y = 15

y = -5x + 15

Substituting y= -5x+15 from first equation into second equation:

3x + 2y = 16

3x + 2·(-5x + 15) = 16

3x - 10x + 30 = 16

-7x + 30 = 16

7x = 30 - 16 = 14

x = 2

Substituting x=2 into the first equation:

5x + y = 15

5(2) + y = 15

10 + y = 15

y = 15 - 10

y = 5

So your final answers are x=2 and y=5.

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2 years ago
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Answer:

Step-by-step explanation:

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A airplane travels a speed of 300 miles per hour how far in miles will the air plane travel in 20 minutes decmal or fraction ans
Ierofanga [76]

Answer: 15 or \frac{15}{1}

Step-by-step explanation:

We need to divide 300 by 20.

We get 15 or \frac{15}{1}.

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