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inn [45]
2 years ago
14

I need help with Standard Deviation!

Mathematics
1 answer:
Naily [24]2 years ago
3 0
<span>A: The middle 95% contain between 23.8 and 24.2 oz.(2 SDs under and over the mean) B: Approximately 68% of boxes have between 23.9 and 24.1 oz of cereal (1 SD under and over the mean) C: 2.5% of boxes contain more than 24.2, because 95% are within 2 SDs, and that includes lower and higher extremes. D: 16% of boxes have more than 24.1, because 68% are within 1 SD of the mean, so 32 are left, and that includes lower and higher extremes.</span>
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This equation has one soulution 5(x-1)+3x=7(x+1) what is the soulution
Aloiza [94]

Answer:

X=6

Step-by-step explanation:

5(x-1)+3x=7(x+1)

5x-5+3x=7x+1

8x-5=7x+1

8x-7x=1+5

X=6

So the answer is X=6

7 0
2 years ago
Which of the following data sets has the mean, median, mode, and range as the same number?
I am Lyosha [343]

Answer:

A.

Step-by-step explanation:

6, 11,14,14,19,20

Adding these 6 numbers we get  84.

84 / 6 = 14 = mean.

Median =  middle number(s) = 14

Mode = number occurring most = 14.

5 0
1 year ago
You have 10 marbles in a bag: 3 blue, 2 green, 4 yellow, and 1 purple. If you close your eyes and choose a marble at random, wha
Naily [24]

Answer:

3/10

Step-by-step explanation:there are 10 marbles all together three blue ones

4 0
3 years ago
Read 2 more answers
HELP IM IN A QUIZZ... In a certain game, players earn 10 points for each question answered correctly and -5 points for questions
spayn [35]

Answer:

-10

Step-by-step explanation:

Just set up a simple equation.

3 0
2 years ago
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g Use this to find the equation of the tangent line to the parabola y = 2 x 2 − 7 x + 6 at the point ( 4 , 10 ) . The equation o
natali 33 [55]

Answer:

The tangent line to the given curve at the given point is y=9x-26.

Step-by-step explanation:

To find the slope of the tangent line we to compute the derivative of y=2x^2-7x+6 and then evaluate it for x=4.

(y=2x^2-7x+6)'          Differentiate the equation.

(y)'=(2x^2-7x+6)'       Differentiate both sides.

y'=(2x^2)'-(7x)'+(6)'    Sum/Difference rule applied: (f(x)\pmg(x))'=f'(x)\pm g'(x)

y'=2(x^2)'-7(x)'+(6)'  Constant multiple rule applied: (cf)'=c(f)'

y'2(2x)-7(1)+(6)'        Applied power rule: (x^n)'=nx^{n-1}

y'=4x-7+0               Simplifying and apply constant rule: (c)'=0

y'=4x-7                    Simplify.

Evaluate y' for x=4:

y'=4(4)-7

y'=16-7

y'=9 is the slope of the tangent line.

Point slope form of a line is:

y-y_1=m(x-x_1)

where m is the slope and (x_1,y_1) is a point on the line.

Insert 9 for m and (4,10) for (x_1,y_1):

y-10=9(x-4)

The intended form is y=mx+b which means we are going need to distribute and solve for y.

Distribute:

y-10=9x-36

Add 10 on both sides:

y=9x-26

The tangent line to the given curve at the given point is y=9x-26.

------------Formal Definition of Derivative----------------

The following limit will give us the derivative of the function f(x)=2x^2-7x+6 at x=4 (the slope of the tangent line at x=4):

\lim_{x \rightarrow 4}\frac{f(x)-f(4)}{x-4}

\lim_{x \rightarrow 4}\frac{2x^2-7x+6-10}{x-4}  We are given f(4)=10.

\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}

Let's see if we can factor the top so we can cancel a pair of common factors from top and bottom to get rid of the x-4 on bottom:

2x^2-7x-4=(x-4)(2x+1)

Let's check this with FOIL:

First: x(2x)=2x^2

Outer: x(1)=x

Inner: (-4)(2x)=-8x

Last: -4(1)=-4

---------------------------------Add!

2x^2-7x-4

So the numerator and the denominator do contain a common factor.

This means we have this so far in the simplifying of the above limit:

\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}

\lim_{x \rightarrow 4}\frac{(x-4)(2x+1)}{x-4}

\lim_{x \rightarrow 4}(2x+1)

Now we get to replace x with 4 since we have no division by 0 to worry about:

2(4)+1=8+1=9.

6 0
3 years ago
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