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BartSMP [9]
3 years ago
6

Help pls, Which graph correctly shows point A representing z1 − z2 on a complex plane where z1 and z2 are complex numbers?

Mathematics
1 answer:
Marianna [84]3 years ago
4 0

Answer:

The first diagram is the correct one

Step-by-step explanation:

Notice that the subtraction of two complex numbers (z1- z2) implies the use of the opposite for the real and imaginary part of the complex number that is subtracted (in our case of z2). When we do such, the complex number z2 gets reflected about the origin (0,0), and then the real components of the two numbers get added among themselves and the imaginary components get added among themselves.

The diagram that shows such reflection about the origin [ z2 = 3 + 5 i being converted into -3 - 5 i] and then the combination of real parts [-3 + 5 = 2] and imaginary parts [-5 i - 3 i = - 8 i], is the very first diagram shown.

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h = 2A/b

Step-by-step explanation:

multiply both sides by 2

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divide both sides by b

2A/b = h

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Persons having Raynaud's syndrome are apt to suffer a sudden impairment of blood circulation in fingers and toes. In an experime
Citrus2011 [14]

Answer:

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

Step-by-step explanation:

We have to perform a hypothesis test on the difference between means.

The null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2

μ1: mean heat output for subjects with the syndrome.

μ2: mean heat output for non-sufferers.

We will use a significance level of 0.05.

The difference between sample means is:

M_d=\bar x_1-\bar x_2=0.63-2.09=-1.46

The standard error is

s_{M_d}=\sqrt{\sigma_1^2/n_1+\sigma_2^2/n_2}=\sqrt{0.3^2/9+0.5^2/9}=\sqrt{ 0.038 } \\\\ s_{M_d}=0.194

The t-statistic is

t=\dfrac{M_d}{s_{M_d}}=\dfrac{-1.46}{0.194}=-7.52

The degrees of freedom are

df=n_1+n_2-2=9+9-2=16

The critical value for a left tailed test at a significance level of 0.05 and 16 degrees of freedom is t=-1.746.

The t-statistic is below the critical value, so it lies in the rejection region.

The null hypothesis is rejected.

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

5 0
2 years ago
This question is too hard
Aleonysh [2.5K]

Answer:

7.50 is the answer to the question

4 0
2 years ago
Read 2 more answers
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