Question

Using the quadratic formula to solve 11x^2-4x=1, what are the values of X?

Answer 1

The correct answers for x would be $\frac{2 +/- \sqrt{15} }{11}$.

In order to find this, we must first get the equation to equal 0. In order to do that, subtract 1 from each side to get the following. 

11$x^{2}$ - 4x - 1 = 0

Knowing this we can now use the quadratic equation using a = 11, b = -4 and c = -1. The quadratic equation is below. 

$\frac{-b +/- \sqrt{ b^{2} - 4ac} }{2a}$

Now we can plug the values into the equation to solve. 

$\frac{4 +/- \sqrt{ -4^{2} - 4(11)(-1)} }{2(11)}$

Then simplify using the order of operations. 

 $\frac{2 +/- \sqrt{15} }{11}$.