It is true that the product of two consecutive even integers are always one less than the square of their average.
<u>Step-by-step explanation</u>:
Let the two consecutive odd integers be 1 and 3.
- The product of 1 and 3 is (1
3)=3 - The average of 1 and 3 is (1+3)/2 =4/2 = 2
- The square of their average is (2)² = 4
∴ The product 3 is one less than the square of their average 4.
Let the two consecutive even integers be 2 and 4.
- The product of 2 and 4 is (24)=8
- The average of 2 and 4 is (2+4)/2 =6/2 = 3
- The square of their average is (3)² = 9
∴ The product 8 is one less than the square of their average 9.
Thus, It is true that the product of two consecutive even integers are always one less than the square of their average.
Hi!
<h3>To find the prime factorization of a number, keep dividing by the smallest factor that goes into it. </h3>
27/3 = 9
9/3 = 3
3/3 = 1
<u>3 · 3 · 3 = 27</u>
<h2>The answer is C. 3 · 3 · 3</h2>
Hope this helps! :)
-Peredhel
ANSWER
a.)17
EXPLANATION
The given function is
We want to find the remainnder when this function is divided by x-3 using synthetic division.
We write the coefficients of the given function and carry out the synthetic division as shown in the attachment.
The remainnder is 17.
The correct answer is A.
The answer is: " (x² − 3) " .
_________________________________
Explanation:
_________________________________
Given: 3x² <span>− 9x ; factor out a "3x" ;
_________________________________
</span>→ 3x (x² − 3) ;
_________________________________
The answer is: " (x² − 3) " .
_________________________________
1. -3
2. 28
3. 88
4. -5
5. -28
