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sweet-ann [11.9K]
4 years ago
7

What is the difference in time between crossing a bridge that is 2,737 meters long at an average speed of 322 meters per minute

and in crossing the same bridge at an average speed of 80 meters per minute?
Mathematics
1 answer:
egoroff_w [7]4 years ago
3 0

so the bridge is 2737 meters long.

at a speed of 322 m/min, meaning for for every passing minute, there are 322 meters covered, so we can simply divide 2737/322 to get a "minute" amount, namely 8.5, at 322 m/min, it takes 8.5 minutes to cross it.

now, if we instead are going slower, at 80 m/min, 80 meters to a minute, then it'll be 2737/80 minutes, namely 34.2125.

their time difference is 34.2125 - 8.5  = 25.7125 minutes, so about 25 minutes and 43 seconds.

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ZX bisects ∠WZY. If the measure of ∠YXZ is (6m – 12)°, what is the value of m?
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Answer:

The correct answer is option B.  17

Step-by-step explanation:

It is given that, ZX bisects ∠WZY. If the measure of ∠YXZ is (6m – 12)°

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From the figure we can see that, triangle WYZ is an isosceles  triangle.

ZW = ZY

Then <YXZ = <WXZ = 90°

It is given ∠YXZ  = (6m – 12)°

(6m – 12)° =  90°

6m = 90 + 12  = 102

m = 102/6 = 17

Therefore the value of m = 17

The correct answer is option B.  17

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The American Bankers Association reported that, in a sample of 120 consumer purchases in France, 48 were made with cash, compare
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Step-by-step explanation:

Hello!

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You need to construct a 90% CI for the difference of proportions p₁-p₂

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[(p'₁-p'₂) ± Z_{1-\alpha /2} * \sqrt{\frac{p'_1(1-p'_1)}{n_1} +\frac{p'_2(1-p'_2)}{n_2} }]

Z_{0.95}= 1.648

[(0.4-0.4364)±1.648 * \sqrt{\frac{0.4(1-0.4)}{120} +\frac{0.4364(1-0.4364)}{55} }]

[-0.1689;0.0961]

The interval has a negative bond, it is ok, keep in mind that even tough proportions take values between 0 and 1, in this case, the confidence interval estimates the difference between the two proportions. It is valid for one of the bonds or the two bonds of the CI for the difference between population proportions to be negative.

I hope this helps!

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