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3 years ago

What's the elapsed time between 3:40 A.M. and 2:00 P.M.?

Mathematics

2 answers:

Talja [164]3 years ago

7 0

I can not be B that is for sure It is C hoped that helped

matrenka [14]3 years ago

6 0

The answer is C. 10 hours and 20 minutes.

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The fastest speed recorded for a runner is 27 mph. This is 20%of the fastest speed for a water skier. Find the record for a wate

posledela

The answer is 135 mph

6 0

3 years ago

Pls help this is for math ill give a brainly

olasank [31]

Answer: The last one - 5 1/3 divided by 1/6

Step-by-step explanation:

since you are trying to figure out how much she runs a day, u divide

Hope this helps :)

6 0

3 years ago

A chef got 7 bags of onions. The red onions came in bags of 8 and the yellow onions came in bags of 3. If the chef got a total o

frutty [35]

Answer:

$\#\text{ of 8-onion bags: }4,\\\#\text{ of 3-onion bags: }3$

Step-by-step explanation:

Let $a$ be the number of bags with 8 onions and let $b$ be the number of bags with 3 onions. We have the following system of equations:

$\begin{cases}a+b=7,\\8a+3b=41\end{cases}$

Subtracting $b$ from both sides of the first equation, we get $a=7-b$ . Substitute this into the second equation:

$8(7-b)+3b=41,\\56-8b+3b=41,\\56-5b=41,\\-5b=-15,\\b=\boxed{3}$

Therefore, the number of 8-onion bags is:

$a=7-b,\\a=7-3,\\a=\boxed{4}$

Thus, the chef got 4 8-onion bags and 3 3-onion bags.

5 0

3 years ago

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro

Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of $\pi$ , so we use the worst case scenario, which is $\pi = 0.5$

Then

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.03\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.03}$

$(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.03})^{2}$

$n = 1067.11$

Rounding up

A sample of 1068 is needed.

8 0

3 years ago

PLEASE HELP ASAP

Viktor [21]

Answer:

No cheating: you’re starring in a movie w/ the last person saved in your camera roll and the last song you listened to is the title.

"let's go everywhere" the movie with taemin and taeyong sounds like something i would watch ♡ https://t.co/tGdUt7CKPc

4 0

3 years ago