Consecutive integers are 1 apart
they are
x,x+1,x+2
the sum of their squares is 194
x²+(x+1)²+(x+2)²=194
expand
x²+x²+2x+1+x²+4x+4=194
x²+x²+x²+2x+4x+1+4=194
3x²+6x+5=194
minus 5 from both sides
3x²+6x=189
3(x²+2x)=189
divide both sides by 3
x²+2x=63
minus 63 from bot sides
x²+2x-63=0
what 2 numbers multiply to get -63 and add to get 2
-7 and 9
(x-7)(x+9)=0
set each to zero
x-7=0
x=7
x+9=0
x=-9
for x=7
x+1=8
x+2=9
for x=-9
x+1=-8
x+2=-7
the integers are 7,8,9 or -9,-8,-7
159
10 squared is 100
Do the 5+3 next to get 8 then square the 8 to get 64
That leaves you with 100+64-5=159
Answer:
w 2 x 6
Step-by-step explanation:
Answer:
DF = 7.5
Step-by-step explanation:
Since the 3 sides are congruent, then
EF = DE , that is
4.5m - 42 = 1.5m - 9 ( subtract 1.5m from both sides )
3m - 42 = - 9 ( add 42 to both sides )
3m = 33 ( divide both sides by 3 )
m = 11
Thus
DE = 1.5m - 9 = 1.5(11) - 9 = 16.5 - 9 = 7.5
Then
DF = 7.5
