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Dmitry [639]
4 years ago
15

What is 41/6 as a mixed number in simplest form? Enter your answer in the box.

Mathematics
2 answers:
MaRussiya [10]4 years ago
5 0
The answer is as a mixed number is 6 1/6
solmaris [256]4 years ago
3 0

Answer:

6 1/6

Step-by-step explanation:

six goes into 42 seven times that leaves you with one number so it can go in six times evenly and that leaves you with 1/6

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Two satellites are orbiting Earth. The path of one satellite has the equation x^2 + y^2 = 56250000. The orbit of the other satel
ExtremeBDS [4]

Answer:

1,257 km

Step-by-step explanation:

The path of one satellite has the equation

x^2 + y^2 = 56,250,000\\ \\x^2+y^2=7,500^2

This is the equation of the circle with the center at the origin (Eartg) and the radius of 7,500 km.

The orbit of the other satellite is 200 km farther from the centre of Earth, so the radius of this orbit is 7,700 km.

Find the distances travelled by two satellites:

1st satellite:

D_1=2\pi r_1=2\pi \cdot 7,500=15,000\pi \ km

2nd satellite:

D_2=2\pi r_2=2\pi \cdot 7,700=15,400\pi \ km

Difference:

D_2-D_1=15,400\pi -15,000\pi =400\pi \approx 1,257\ km

6 0
4 years ago
Someone help this is due today worth half my grade!!
MAVERICK [17]

Answer:

D-the slope of the line will be zero

Step-by-step explanation:

4 0
4 years ago
given the function f(x)=-x^2+8x+9, state whether the vertex the represents a maximum or minimum point for the function
olga_2 [115]
If you had
ax^2+bx+c
a is the leading term
when a>0, the parabola opens up and therfor has a minimum point and no max since it goes up infinitely

when a<0, the parabola opens down and therefor has a maximum point and not min since it goes down infinitely

-x^2+8x+9
-1<0
opens down
has max
vertex=max
3 0
4 years ago
Read 2 more answers
Expand (a+b)^7 using pascal triangle
Inga [223]

(a+b)^7= a^7+ 7a^7b+ 21 a^6b²+ 35a^5b³+ 35 a⁴b⁴+ 21 a³b^5 + 7a²b^6 + b^7

8 0
3 years ago
What's the concavity of f(x)=x^2+4x
Anna71 [15]
\bf f(x)=x^2+4x\qquad \cfrac{df}{dx}=2x+4\qquad \boxed{f''(x)=2}\impliedby &#10;\begin{array}{llll}&#10;\textit{just a positive}\\&#10;constant&#10;\end{array}

there are no inflection points, because it never changes concavity, is just a constant and thus for any region over the x-axis, will always be a positive value, and thus is always "concave up".
8 0
3 years ago
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