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sasho [114]
3 years ago
9

Can you help me find out weather 6, 36,and 48 are a factor multiple or neither of 24.

Mathematics
1 answer:
nlexa [21]3 years ago
5 0
Factors are the multiplier and the multiplicand in the mathematical operation called multiplication.

Multiple is the any number multiplied by any integer.

Factors of 24:
1, 2, 3, 4, 6, 8, 12, 24

Multiples of 24:
24, 48, 72, 96, 120, so on.

6 is a factor of 24.
36 is neither a factor nor a multiple of 24.
48 is a multiple of 24.
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Step-by-step explanation:

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2 years ago
A bagel shop sold 8 plain bagels and 13 rye bagels. What is the ratio of the number of rye bagels to the number of plain bagels
marshall27 [118]

Answer:

13 : 8

Step-by-step explanation:

Number of plain bagels sold = 8

Number of rye bagels sold = 13

Ratio of the number of rye bagels to the number of plain bagels sold = 13 : 8

Also written as

13/8

Or

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3 years ago
- 7th Grade work -<br><br> Pls just say if it's a, b, c, or d.
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4 0
3 years ago
Read 2 more answers
130 is 65% of what number?
mina [271]
X - the number

65\% x=130 \\&#10;\frac{65}{100}x=130 \\&#10;\frac{13}{20}x=130 \\&#10;x=130 \times \frac{20}{13} \\&#10;x=10 \times 20 \\&#10;x=200

130 is 65% of 200.
4 0
4 years ago
The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 55 o
Usimov [2.4K]

Answer:

a) For this case and using the empirical rule we can find the limits in order to have 9% of the values:

\mu -2\sigma = 55 -2*6 =43

\mu +2\sigma = 55 +2*6 =67

95% of the widget weights lie between 43 and 67

b) For this case we know that 37 is 3 deviations above the mean and 67 2 deviations above the mean since within 3 deviation we have 99.7% of the data then the % below 37 would be (100-99.7)/2 = 0.15% and the percentage above 67 two deviations above the mean would be (100-95)/2 =2.5% and then we can find the percentage between 37 and 67 like this:

100 -0.15-2.5 = 97.85

c) We want to find the percentage above 49 and this value is 1 deviation below the mean so then this percentage would be (100-68)/2 = 16%

Step-by-step explanation:

For this case our random variable of interest for the weights is bell shaped and we know the following parameters.

\mu = 55, \sigma =6

We can see the illustration of the curve in the figure attached. We need to remember that from the empirical rule we have 68% of the values within one deviation from the mean, 95% of the data within 2 deviations and 99.7% of the values within 3 deviations from the mean.

Part a

For this case and using the empirical rule we can find the limits in order to have 9% of the values:

\mu -2\sigma = 55 -2*6 =43

\mu +2\sigma = 55 +2*6 =67

95% of the widget weights lie between 43 and 67

Part b

For this case we know that 37 is 3 deviations above the mean and 67 2 deviations above the mean since within 3 deviation we have 99.7% of the data then the % below 37 would be (100-99.7)/2 = 0.15% and the percentage above 67 two deviations above the mean would be (100-95)/2 =2.5% and then we can find the percentage between 37 and 67 like this:

100 -0.15-2.5 = 97.85

Part c

We want to find the percentage above 49 and this value is 1 deviation below the mean so then this percentage would be (100-68)/2 = 16%

4 0
4 years ago
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