Hello!
We can write this as the system of equations below. We have boxes A, B, and C.
A+B+C=9
B=A+1
C=B+1
First of all we can plug our B and C values into the first equation and solve for A.
A+A+1+A+1+1=9
3a+3=9
3a=6
a=2
Now we can plug our a value into the other equations.
B=2+1
B=3
C=3+1
C=4
Therefore, there are 2 rocks in one box, three in another, and 4 in the last.
I hope this helps!
Answer:
-7/2
Step-by-step explanation:
Answer:
<h2>

</h2>
Step-by-step explanation:
g(x) = x² - 2x - 6
h(x) = 2x² - 5x + 2
To find (h-g) (-2) we must first find h - g(x)
To find h - g(x) subtract g(x) from h(x)
We have
<h3>

</h3><h3>

</h3>
To find (h-g) (-2) substitute the value of x that's - 2 into (h - g)(x) that's replace every x in (h - g)(x) by - 2
That's
<h3>

</h3>
We have the final answer as
<h3>

</h3>
Hope this helps you