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spayn [35]
3 years ago
10

Many states run lotteries to raise money. A website advertises that it knows​ "how to increase YOUR chances of Winning the​ Lott

ery." They offer several systems and criticize others as foolish. One system is called Lucky Numbers. People who play the Lucky Numbers system just pick a​ "lucky" number to​ play, but maybe some numbers are luckier than others.​ Let's use a simulation to see how well this system works. To make the situation​ manageable, simulate a simple lottery in which a single digit from 00 to 99 is selected as the winning number. Any value can be​ picked, but for this​ exercise, pick 1 as the lucky number. What proportion of the time do you​ win
Mathematics
1 answer:
Crank3 years ago
5 0

Complete question is;

Many states run lotteries to raise money. A website advertises that it knows "how to increase YOUR chances of Winning the Lottery." They offer several systems and criticize others as foolish. One system is called Lucky Numbers. People who play the Lucky Numbers system just pick a "lucky" number to play, but maybe some numbers are luckier than others. Let's use a simulation to see how well this system works. To make the situation manageable, simulate a simple lottery in which a single digit from 0 to 9 is selected as the winning number. Any value can be​ picked, but for this​ exercise, pick 1 as the lucky number. What proportion of the time do you​ win?

Answer:

10%

Step-by-step explanation:

We are told that To make the situation manageable, simulate a simple lottery in which a single digit from 0 to 9 is selected as the winning number.

This means the total number of single digits that could possibly be a winning one is 10.

Since we are told that only 1 can be picked, thus;

Probability of winning is; 1/10 = 0.1 or 10%

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Answer the question in the picture
Svet_ta [14]
<h3>Answer:</h3>
  • left picture (bottom expression): -cot(x)
  • right picture (top expression): tan(x)
<h3>Step-by-step explanation:</h3>

A graphing calculator can show you a graph of each expression, which you can compare to the offered choices.

_____

You can make use of the relations ...

... sin(a)+sin(b) = 2sin((a+b)/2)cos((a-b)/2)

... cos(a)+cos(b) = 2cos((a+b)/2)cos((a-b)/2)

... cos(a)-cos(b) = -2sin((a+b)/2)sin((a-b)/2)

Then you have ...

\dfrac{\cos{2x}-\cos{4x}}{\sin{2x}+\sin{4x}}=\dfrac{2\sin{3x}\sin{x}}{2\sin{3x}\cos{x}}=\dfrac{\sin{x}}{\cos{x}}=\tan{x}

and ...

\dfrac{\cos{2x}+\cos{4x}}{\sin{2x}-\sin{4x}}=\dfrac{2\cos{3x}\cos{x}}{-2\cos{3x}\sin{x}}=\dfrac{-\cos{x}}{\sin{x}}=-\cot{x}


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4 years ago
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3 years ago
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Answer:

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