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kirza4 [7]
3 years ago
15

Five spheres are being painted for a display at a store. If the diameter of each sphere is

Mathematics
1 answer:
ivanzaharov [21]3 years ago
4 0
<h2>Hello!</h2>

The answer is:

The total area is:

TotalArea=192.4cm^{2}

<h2>Why?</h2>

To find the cloasest value to the total surface area that will be painted, we need to calculate the area of a single sphere, and then, multiply it by 5.

We know that the diameter of each sphere is 7 centimeters, so, calculating we have:

Calculating the radius we have,

diameter=2*radius\\\\radius=\frac{diameter}{2}=\frac{7cm}{2}=3.5cm

Then, calculating the area, we have:

Area=\pi radius^{2}

Area=\pi 3.5cm^{2}=38.49cm^{2}

Now that we have calculated the surface area of a single sphere, we need to calculate the area of the five spheres.

So, calculating we have:

TotalArea=5*38.48cm^{2}=192.4cm^{2}

Hence, the total area is:

TotalArea=192.4cm^{2}

Have a nice day!

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The sum of the first n odd numbers is n squared! So, the short answer is that the sum of the first 70 odd numbers is 70 squared, i.e. 4900.

Allow me to prove the result: odd numbers come in the form 2n-1, because 2n is always even, and the number immediately before an even number is always odd.

So, if we sum the first N odd numbers, we have

\displaystyle \sum_{i=1}^N 2i-1 = 2\sum_{i=1}^N i - \sum_{i=1}^N 1

The first sum is the sum of all integers from 1 to N, which is N(N+1)/2. We want twice this sum, so we have

\displaystyle 2\sum_{i=1}^N i = 2\cdot\dfrac{N(N+1)}{2}=N(N+1)

The second sum is simply the sum of N ones:

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So, the final result is

\displaystyle \sum_{i=1}^N 2i-1 = 2\sum_{i=1}^N i - \sum_{i=1}^N 1 = N(N+1)-N = N^2+N-N = N^2

which ends the proof.

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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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Marizza181 [45]
To get equivalent decimals you times the decimal by a number for example 2 
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adoni [48]

Answer:

<h2>-38</h2>

Step-by-step explanation:

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Follow the PEDMAS order of operation

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4 0
3 years ago
Read 2 more answers
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