Answer: (f-g)(2)=14
Step-by-step explanation:
(f – g) (-2) means the same as subtracting f(2) and g(2). Since we are given f(x) and g(x), we can use them to solve. There are two ways to solve. One is to find f(2) and g(2), and then subtract them. Another way is to do (f-g)(x), then plug in x=2. I will show both methods.
Method 1
f(2)=3(2)²+1 [exponent]
f(2)=3(4)+1 [multiply]
f(2)=12+1 [add]
f(2)=13
g(2)=1-(2) [subtract]
g(2)=-1
(f-g)(2)=13-(-1) [subtract f(2) and g(2)]
(f-g)(2)=14
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Method 2
(f-g)(x)=3x²+1-(1-x) [distribute -1]
(f-g)(x)=3x²+1-1+x [combine like terms]
(f-g)(x)=3x²+x
(f-g)(2)=3(2)²+2 [plug in x=2, exponent]
(f-g)(2)=3(4)+2 [multiply]
(f-g)(2)=12+2 [add]
(f-g)(2)=14
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Now, we know that (f-g)(2)=14. We confirmed this with both methods.
Answer:
n = 19/18
Step-by-step explanation:
Given:
11/6 = n + 7/9
Find n
11/6 = n + 7/9
Subtract 7/9 from both sides of the equation
11/6 - 7/9 = n + 7/9 - 7/9
11/6 - 7/9 = n
(99-42) / 54 = n
n = 57/54
n = 19/18
Answer: (2, 18)
Step-by-step explanation:
When x=2, 
.
So, it should pass through (2, 18).
You can sort them on the shapes that are the same or different
The number of full periods and classes does a 202-digit number have are 1 and 3 respectively.
<h3>What are periods?</h3>
Periods are simply groups of three digits separated by commas when writing numbers in standard form.
The digit number, 202 has 1 period.
Classes is simply the number of digits in a set.
Example: 500 has 3 classes
We can say that the 202 digit number has 1 period and three classes.
Thus, the number of full periods and classes does a 202-digit number have are 1 and 3 respectively.
Learn more about period here:
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