Answer:
P_min = 490 N/m²
P_max = 7350 N/m²
Explanation:
Formula for pressure is;
Pressure = Force/Area
We are given;
Mass = 30 kg
Dimensions of Block = 0.1 m by
0.4 m by 1.5 m.
Force(weight) = mg = 30 × 9.8 = 294 N
For minimum pressure, it will be at maximum area.
Max area will be at biggest dimensions.
Max area = 0.4 × 1.5 = 0.6 m²
P_min = 294/0.6
P_min = 490 N/m²
Similarly, maximum pressure will be at minimum area.
Minimum area = 0.1 × 0.4 = 0.04 m²
P_max = 294/0.04
P_max = 7350 N/m²
Higher frequency for lower wavelength...
.... If speed is fixed. ie no medium change.
Do you have a book about it? or if you have a dictionary?
Answer:
8.5
Explanation:
to find efficiency take the ratio between the output and input
85/100=output/input
Answer:
4,444,471 m/s
Explanation:
Use the momentum-impulse equation to find the change in velocity:
I = Δp = mΔv
We know the impulse given as well as the mass, we are trying to find the change in velocity hence the question how fast the car is going afterwards.
8.0*10^9 = 1800Δv
Simply divide 1800 to isolate Δv which gives:
4.4*10^6 = Δv
According to the calculator, the 4 is repetitive across all values so therefore it gives:
4,444,444 m/s = Δv
Now find the final/afterwards velocity:
vi + Δv = vf
27 + 4,444,444 = vf
4,444,471 = vf
The impulse given by the engine is out of this world quite literally.