A: (x + 5i)^2
= (x + 5i)(x + 5i)
= (x)(x) + (x)(5i) + (5i)(x) + (5i)(5i)
= x^2 + 5ix + 5ix + 25i^2
= 25i^2 + 10ix + x^2
B: (x - 5i)^2
= (x + - 5i)(x + - 5i)
= (x)(x) + (x)(- 5i) + (- 5i)(x) + (- 5i)(- 5i)
= x^2 - 5ix - 5ix + 25i^2
= 25i^2 - 10ix + x^2
C: (x - 5i)(x + 5i)
= (x + - 5i)(x + 5i)
= (x)(x) + (x)(5i) + (- 5i)(x) + (- 5i)(5i)
= x^2 + 5ix - 5ix - 25i^2
= 25i^2 + x^2
D: (x + 10i)(x - 15i)
= (x + 10i)(x + - 15i)
= (x)(x) + (x)(- 15i) + (10i)(x) + (10i)(- 15i)
= x^2 - 15ix + 10ix - 150i^2
= - 150i^2 + 5ix + x^2
Hope that helps!!!
Answer: 23.4 is the answer
Answer:
20%
Step-by-step explanation:
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Answer:
On a unit circle, the point that corresponds to an angle of is at position .
The point that corresponds to an angle of is at position .
Step-by-step explanation:
On a cartesian plane, a unit circle is
- a circle of radius ,
- centered at the origin .
The circle crosses the x- and y-axis at four points:
Join a point on the circle with the origin using a segment. The "angle" here likely refers to the counter-clockwise angle between the positive x-axis and that segment.
When the angle is equal to , the segment overlaps with the positive x-axis. The point is on both the circle and the positive x-axis. Its coordinates would be .
To locate the point with a angle, rotate the segment counter-clockwise by . The segment would land on the positive y-axis. In other words, the -point would be at the intersection of the positive y-axis and the circle. Its coordinates would be .