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3 years ago

PLEASE HELP! See image. Which relation is a function?

Mathematics

1 answer:

stira [4]3 years ago

7 0

Answer:

The answer to this is the lower right option.

Step-by-step explanation:

Just remember that no two points can share the same x.

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A water tank has a square base of area 5 square meters. Initially the tank contains 70 cubic meters. Water leaves the tank, star

ANEK [815]

Answer:

$9.2\ \text{m}$

Step-by-step explanation:

$b$ = Surface area of base = 5 square meters

Volume of water in tank = 70 cubic meters

The rate at which the volume is reducing is

$\dfrac{dV}{dt}=2+4t\\\Rightarrow dV=2+4tdt$

Integrating from $t=0$ to $t=3$

$V=\int^3_0(2+4t)dt\\\Rightarrow V=2t+2t^2|_0^3\\\Rightarrow V=2\times 3+2\times 3^2-0\\\Rightarrow V=24$

Volume of water remaining in the tank is $70-24=46\ \text{m}^3$

Suface area of base $\times$ depth = Volume

$5\times d=46\\\Rightarrow d=\dfrac{46}{5}\\\Rightarrow d=9.2\ \text{m}$

The depth of the water remaining in the tank is $9.2\ \text{m}$ .

3 0

3 years ago

Please help [99 points]

Luda [366]

The graph shows a nonlinear function. This is because the line is not straight. I hope this helps :) <span />

5 0

2 years ago

Read 2 more answers

AM is a median in △ABC (M∈ BC ). A line drawn through point M intersects AB at its midpoint P. Find areas of △APC and △PMC, if A

Snowcat [4.5K]

Answer:

The area of APC is 70m². The area of triangle PMC is 35m².

Step-by-step explanation:

Let the area of triangle ABC be x.

It is given that AM is median, it means AM divides the area of triangle in two equal parts.

$\text{Area of }\triangle ACM=\text{Area of }\triangle ABM=\frac{x}{2}$ .....(1)

The point P is the midpoint of AB, therefore the area of APC and BPC are equal.

$\text{Area of }\triangle APC=\text{Area of }\triangle BPC=\frac{x}{2}$ ......(2)

The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.

$\text{Area of }\triangle APM=\text{Area of }\triangle BPM=\frac{x}{4}$ .....(3)

The area of triangle APM is 35m².

$\text{Area of }\triangle APM=\frac{x}{4}$

$35=\frac{x}{4}$

$x=140$

Therefore the area of triangle ABC is 140m².

Using equation (2).

$\text{Area of }\triangle APC=\frac{x}{2}$

$\text{Area of }\triangle APC=\frac{140}{2}$

$\text{Area of }\triangle APC=70$

Therefore the area of triangle APC is 70m².

Using equation (3), we can say that the area of triangle BPM is 35m² and by using equation (2), we can say that the area of triangle BPC is 70m².

$\triangle BPC=\triangle BPM+\triangle PMC$

$70=35+\triangle PMC$

$35=\triangle PMC$

Therefore the area of triangle PMC is 35m².

8 0

3 years ago

A cube has side length a. The side lengths are decreased to 20% of their original size. Write an expression in simplest form for

Travka [436]

Answer:

0.512a³ cubic units

Step-by-step explanation:

Given a cube of length, a, then when decreased by 20%, what's left is actually 80% of the original. So, for this case, we have a cube with a length of 80%(a) = 0.80a.

Now, to compute for the volume of a cube, we multiply the length three times to itself. Or, in other words, raise the length to the third power. That means the volume of the new cube is (0.8a)³ = 0.512a³ cubic units.

3 0

2 years ago

Read 2 more answers

What is the value of x if x/4+2=15<br>Help!

NNADVOKAT [17]

Answer:

Step-by-step explanation:

because i don't know if the 2 is with the 4 or not I have calculated both.

x/4 + 2 = 15

<=> x/4 = 13

<=> x = 13.4 = 52

x/(4+2) = 15

<=> x/6 = 15

<=> x = 6.15 = 90

8 0

2 years ago

Read 2 more answers