Answer:
(2^2)^3/2 = (2)^3 = 8
Step-by-step explanation:
So to solve (4)^3/2 ,you have to realise that you need to remove the denominator in the exponent value which in this case is 2
In order to remove the 2,you would need a 2 in the numerator of the exponent .While understanding all this the value 4 can be equated as 2^2.
Thus your means of getting a 2 in the numerator is solved by simply replacing the 4 with 2^2
Thus what you will get is (2^2)^3/2
Now we have a property in exponent where
(x^m)^n = (x)^mn
Thus (2^2)^3/2 = (2)^3 =8
A/d c/h e/f g/b :) I think
The intersection of the diagonals of a parallelogram is always the midpoint of each of the diagonals, which means all we have to do is grab two opposite vertices and average their coordinates.
<span>Let's use W and Y. </span>
<span>(-1 + 6)/2 = 2.5 </span>
<span>(7 + -2)/2 = 2.5 </span>
<span>So our point is (2.5,2.5) </span>
<span>We could also use X and Z. </span>
<span>(8 + -3)/2 = 2.5 </span>
<span>(7 + -2)/2 = 2.5 </span>
<span>Again, we get (2.5,2.5)</span>
Answer:
11 hope this helps you and write
