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MissTica
3 years ago
15

Two laboratory technicians are running product quality tests . One technician takes 6 minutes less than the other . What equatio

n would give the amount of time , t , it would take to run the tests if the technicians work together to split the work on the different tests ? 1/(6t) = 1/x - 1/(x - 6) B 1/t = 1/x + 1/(x - 6) Oct t = x + x - 6 1/t = 1/x - 1/(x - 6)
Mathematics
1 answer:
Georgia [21]3 years ago
6 0

Answer:

<h3>C. t = x + x - 6</h3>

Step-by-step explanation:

Let the time use by other one technician be x

if the other technician takes 6 minutes less than the first technician, then the time taken by the other technician will (x - 6)

The total amount of time t it would take to run the tests if the technicians work together will be expressed by taking the sum of the time taken by the two technician as shown.

First technician = x

Second technician = x-6

Sum of the time taken

t = x+ (x-6)

Hence option C is correct

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\huge \boxed{54 \:  \:  {units}^{2} }

Step-by-step explanation:

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What is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)?
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<u>SOLUTION: </u>

Given that, we have to find what is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)  

We know that, distance between two points P\left(x_{1}, y_{1}\right) \text { and } Q\left(x_{2}, y_{2}\right) is given by  

P Q=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

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\begin{array}{l}{\text { Distance between }(-5,-1) \text { and }(-5,5)=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {\qquad \begin{array}{l}{=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(0)^{2}+(5+1)^{2}}=\sqrt{(6)^{2}}=6} \\\\ {=\sqrt{(-5)^{2}+(5+1)^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(-8)^{2}+(5+1)^{2}}=\sqrt{64+36}=\sqrt{100}=10} \\\\ {=\sqrt{(3-1)^{2}+(-1-(-1))^{2}}} \\\\ {=\sqrt{(5+3)^{2}+(0)^{2}}=\sqrt{(8)^{2}}=8}\end{array}}\end{array}

8 0
3 years ago
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