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Anit [1.1K]
3 years ago
8

M/n=p-6 what is n how to solve

Mathematics
1 answer:
madreJ [45]3 years ago
4 0
M/n=p-6
n= m/(p-6)
i swapped the n and p-6
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. <br> Evaluate: 0.234 x 102.<br> 23,400<br> 234<br> 2.34<br> 23.4
inn [45]
Answer:

23.4

Explanation:

This is the closest answer to the answer I got, it might be wrong and it might not. My answer was 23.8!
4 0
2 years ago
there are three oranges in 200g of bag . if the weight of them with bag is 1.4kg. find the weight of an orange.i want full metho
Lana71 [14]

the bag is 200g

total weight with oranges is 1400g

deduct the bags weight from total weight

1400 - 200

1200g

this is the weight of the three oranges

so each orange would be

1200 ÷ 3

400g

4 0
3 years ago
For each container of tea, McKenzie uses 16 tea bags and 3 cups of sugar. If McKenzie uses 64 tea bags, how many cups of sugar w
cestrela7 [59]
So tis is a ratio  16 is to 3 or 16:3
if use 64 tea bags then how many cups of sugar so
turn 16:3 into fraction
16:3=16/3 or 3/16, it doesn't matter
then you want to find 64:x or 64/x or x/64

we know that 16/3=64/x because it tis an equivalent ratio
so 16/3=64/x
multiply both sdies by (3 times x)
16 times x times 3/3=64 times 3 times x/x
16 times x=64 times 3
16x=192
divide both sdies by 16
x=12
theanswer is 12 cups of sugar
5 0
3 years ago
If f(x) = 3x – 2 and g(x) = 2x + 1, find (f + g)(x). please help :C
Luba_88 [7]
(f+g)(x) = f(x) + g(x)

(f+g)(x) = 3x-2 + 2x+1

(f+g)(x) = (3x+2x) + (-2+1)

(f+g)(x) = 5x - 1
3 0
3 years ago
Read 2 more answers
A consumer organization inspecting new cars found that many had appearance defects (dents, scratches, paint chips, etc.). While
Murljashka [212]

Answer:

The expected number of appearance defects in a new car  = 0.64

standard deviation = 0.93(approximately)

Step-by-step explanation:

Given -

7% had exactly three, 11% exactly two, and 21% only one defect in cars.

Let X be no of defects in a car

P(X=3) = .07 , P(X=2) = .11 , P(X=3) = .21

P(X=0 ) = 1 - .07 - .11 - .21 = 0.61

The expected number of appearance defects in a new car =

E(X) = \nu = = \sum X P(X) =3\times 0.07 + 2\times0.11 + 3\times0.21 + 0\times0.61 = 0.64

\sigma^{2}  = variation of E(X) = \sum (X - \nu) ^{2}P(X) = (3 - 0.64) ^{2}\times0.07 + (2 - 0.64) ^{2}\times0.11 + (1 - 0.64) ^{2}\times0.21 + (0 - 0.64) ^{2}\times0.61

 = (2.36) ^{2}\times0.07 + (1.36) ^{2}\times0.11 + (.36) ^{2}\times0.21 + ( 0.64) ^{2}\times0.61 = 0.8704

standard deviation  =  \sqrt{\sigma^{2}} = \sqrt{0.8704^{2}} = 0.93(approximately)

4 0
3 years ago
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