What is the equation of the line show In this graph? ASAP!! Please

Grades on a standardized test are known to have a mean of 1000 for students in the United States. The test is administered to 45

vovikov84 [41]

Answer:

a. The 95% confidence interval is 1,022.94559 < μ < 1,003.0544

b. There is significant evidence that Florida students perform differently (higher mean) differently than other students in the United States

c. i. The 95% confidence interval for the change in average test score is; -18.955390 < μ₁ - μ₂ < 6.955390

ii. There are no statistical significant evidence that the prep course helped

d. i. The 95% confidence interval for the change in average test scores is 3.47467 < μ₁ - μ₂ < 14.52533

ii. There is statistically significant evidence that students will perform better on their second attempt after the prep course

iii. An experiment that would quantify the two effects is comparing the result of the confidence interval C.I. of the difference of the means when the student had a prep course and when the students had test taking experience

Step-by-step explanation:

The mean of the standardized test = 1,000

The number of students test to which the test is administered = 453 students

The mean score of the sample of students, $\bar{x}$ = 1013

The standard deviation of the sample, s = 108

a. The 95% confidence interval is given as follows;

$CI=\bar{x}\pm z\dfrac{s}{\sqrt{n}}$

At 95% confidence level, z = 1.96, therefore, we have;

$CI=1013\pm 1.96 \times \dfrac{108}{\sqrt{453}}$

Therefore, we have;

1,022.94559 < μ < 1,003.0544

b. From the 95% confidence interval of the mean, there is significant evidence that Florida students perform differently (higher mean) differently than other students in the United States

c. The parameters of the students taking the test are;

The number of students, n = 503

The number of hours preparation the students are given, t = 3 hours

The average test score of the student, $\bar{x}$ = 1019

The number of test scores of the student, s = 95

At 95% confidence level, z = 1.96, therefore, we have;

The confidence interval, C.I., for the difference in mean is given as follows;

$C.I. = \left (\bar{x}_{1}- \bar{x}_{2} \right )\pm z_{\alpha /2}\sqrt{\dfrac{s_{1}^{2}}{n_{1}}+\dfrac{s_{2}^{2}}{n_{2}}}$

Therefore, we have;

$C.I. = \left (1013- 1019 \right )\pm 1.96 \times \sqrt{\dfrac{108^{2}}{453}+\dfrac{95^{2}}{503}}$

Which gives;

-18.955390 < μ₁ - μ₂ < 6.955390

ii. Given that one of the limit is negative while the other is positive, there are no statistical significant evidence that the prep course helped

d. The given parameters are;

The number of students taking the test = The original 453 students

The average change in the test scores, $\bar{x}_{1}- \bar{x}_{2}$ = 9 points

The standard deviation of the change, Δs = 60 points

Therefore, we have;

C.I. = $\bar{x}_{1}- \bar{x}_{2}$ + 1.96 × Δs/√n

∴ C.I. = 9 ± 1.96 × 60/√(453)

i. The 95% confidence interval, C.I. = 3.47467 < μ₁ - μ₂ < 14.52533

ii. Given that both values, the minimum and the maximum limit are positive, therefore, there is no zero (0) within the confidence interval of the difference in of the means of the results therefore, there is statistically significant evidence that students will perform better on their second attempt after the prep course

iii. An experiment that would quantify the two effects is comparing the result of the confidence interval C.I. of the difference of the means when the student had a prep course and when the students had test taking experience

5 0

2 years ago

Adding and subtracting functions g(x) = 2x f (x) = −2x^3 + 2x Find g(x) + f (x)

Lera25 [3.4K]

Answer:

free points thanks

Step-by-step explanation:

7 0

2 years ago

The explicit rule for a sequence is an=5(−2)^n−1

Murrr4er [49]

Answer:

3) $a_n=-2a_{n-1}$ , $a_1=5$

Step-by-step explanation:

Given that the explicit rule for a sequence is $a_n=5(-2)^{n-1}$ .

Now we need to find about what is the recursive rule for the sequence and match with the given choices to find the correct choice.

1) $a_n=-2a_{n+1}$ , $a_1=5$

2) $a_n=-5a_{n+1}$ , $a_1=2$

3) $a_n=-2a_{n-1}$ , $a_1=5$

4) $a_n=-5a_{n-1}$ , $a_1=2$

Plug n=1 into given formula to get first term

$a_n=5(-2)^{n-1}$

$a_1=5(-2)^{1-1}=5(-2)^{0}=5(1)=5$

base of the exponent part is (-2) so that means we need to multiply -2 to the previous term to get nth term

Hence correct choice is: 3) $a_n=-2a_{n-1}$ , $a_1=5$

7 0

2 years ago

By decreasing each dimension by 1 unit, the area of a rectangle decrease from 40 square feet (on the left) to 28 square feet (on

Anettt [7]

The was a 30% decrease in area. You started with 40 sq ft and ended up with 28 sq ft. So you lost 40 - 28 = 12 sq ft. Now you need to figure out what percentage of 40 is 12. For that you just simply divide 12 / 40 = 0.30 And to convert 0.30 from a decimal to a percentage, just multiply by 100. 0.30 * 100 = 30%

8 0

3 years ago

If DE=6x what is the perimeter of the triangle in terms of x? A 6 B 18 C 18x

tatyana61 [14]

May be another Lala La La La La La La La La La La La La La La La La La La la la la la la la la la la la la la la la la la la la la la la la la la la la la la la la la la la la la la la la la la la la la la la la la la

6 0

2 years ago