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garik1379 [7]
3 years ago
7

Can some one help please help me

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
5 0

Answer:

5\:\:and\:\:7 are the required consecutive odd integers.

Step-by-step explanation:

Let's say, the two consecutive odd integers be, x and x+2.

x\left(x+2\right)=2\left(x+2\right)+21\\\\x^2+2x=2x+4+21\\\\\mathrm{Subtract\:}2x\mathrm{\:from\:both\:sides}\\\\x^2+2x=2x+25\\\\x^2+2x-2x=2x+25-2x\\\\x^2=25\\\\x=5

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The absolute value is always positive, so the numbers would be 4 and 4. 
Those are two equal numbers so it is: equal to
Hope this helps. 
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If x does not equal 16 then 2x+10 does not equal 42​
Lady bird [3.3K]

Answer:

The answer is

True

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On the 1st January 2014 Carol invested some money in a bank account.
Ghella [55]

Answer:

\large \boxed{\text{\pounds 23 360.00}}

Step-by-step explanation:

The formula for the accrued amount from compound interest is

A = P \left(1 + \dfrac{r}{n}\right)^{nt}

1. Amount in account on 1 Jan 2015

(a) Data:

a = £23 517.60

r = 2.5 %

n = 1

t = 1 yr

(b) Calculations:  

r = 0.025

\begin{array}{rcl}23517.60 & = & P\left (1 + \dfrac{r}{n}\right)^{nt}\\\\& = & P\left (1 + \dfrac{0.025}{1}\right)^{1\times1}\\\\& = & P (1 + 0.025)\\ & = & 1.025 P\\P & = & \dfrac{23517.60 }{1.025} \\\\& = & 22 944.00 \\\end{array}

The amount that gathered interest was £22 944.00 but, before the interest started accruing, Carol had withdrawn £1000 from the account.

She must have had £23 944 in her account on 1 Jan 2015.

(2) Amount originally invested

(a) Data

A = £23 944.00

\begin{array}{rcl}23 944.00 & = & 1.025 P\\P & = & \dfrac{23 944.00 }{1.025} \\\\& = & \mathbf{23 360.00} \\\end{array}\\\text{Carol originally invested $\large \boxed{\textbf{\pounds23 360.00}}$ in her account.}

3. Summary

1 Jan 2014      P = £23 360.00

1 Jan 2015     A =    23 944.00

     Withdrawal = <u>    -1  000.00 </u>

                     P =     22 944.00

1 Jan 2016    A =    £23 517.60

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3 years ago
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( 6 units)  * ( 9 units) * (7 units)  = (6 * 9 * 7) units³ =  378 units³ .
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I need this answered
Ilya [14]
Hope this makes sense! It was too hard to type out lol. The one on the left is how it is solved the and one on the right kinda explains how I got the equation.

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