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Sati [7]
3 years ago
12

A person who weighs 45 2/5 kg on Earth would weigh 107 kg on Saturn. If s represents a person's weight in kg, on Saturn, which p

roportion could you solve to determine the weight on Saturn of a person who weighs 73 1/2 kg on Earth?

Mathematics
2 answers:
padilas [110]3 years ago
5 0

There right the answer is D thank you so much

sleet_krkn [62]3 years ago
4 0

Answer: D. \frac{45\frac{2}{5}}{107}=\frac{73\frac{1}{2}}{s}

Step-by-step explanation:

Firstly, we know the weight of a person (let's call it person 1) is 45\frac{2}{5}kg and the weight of the same person 1 on Saturn is 107kg.

Now, we want to know the weight of a second person (person 2) on Saturn, but we only know its weight on Earth, which is 73\frac{1}{2}kg.

This problem can be solved by the Rule of Three, which is mathematical rule to find out an amount that is with another quantity given in the same relation as other two also known:

Earth     Saturn

45\frac{2}{5}kg ------- 107kg

73\frac{1}{2}kg -------- s

Finding  s:

s=\frac{(73\frac{1}{2}kg)(107kg)}{45\frac{2}{5}kg}

Rearranging the equation:

\frac{45\frac{2}{5}}{107}=\frac{73\frac{1}{2}}{s}

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Jane’s score on her first text was 72%.On Her second test she received a score of 81%. What was her percent increase?
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Evaluate the expression: 16P4
Tju [1.3M]

The expression 16p⁴ will be written as (2p)⁴.

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

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The given expression will be solved as below:-

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