The answer to this is 36.
Answer:
Step-by-step explanation:
<u>Taylor series</u> expansions of f(x) at the point x = a
This expansion is valid only if 
exists and is finite for all 
, and for values of x for which the infinite series converges.
Substituting the values in the series expansion gives:
Factoring out e⁴:
![e^{4x}=e^4\left[1+4(x-1)+8}(x-1)^2+...\right]](https://tex.z-dn.net/?f=e%5E%7B4x%7D%3De%5E4%5Cleft%5B1%2B4%28x-1%29%2B8%7D%28x-1%29%5E2%2B...%5Cright%5D)
<u>Taylor Series summation notation</u>:
Therefore:
Answer
Find out the m∠6 .
To prove
As given
a∥e , m∥n , and m∠2 = 112°.
As m∥n
a is the transversal (A line that cuts across two or more (usually parallel) lines is called transverasl.)
Thus
∠ 2 = ∠3 ( Corresponding angle property )
∠3 = 112°
Also
a∥e and m is transversal .
∠ 3 = ∠6 = 112 ° ( Corresponding angle property )
Therefore
∠6 = 112°
Answer:
11 1/5
Step-by-step explanation:
3 1/2 + 2 57/60 + 4 3/4 =
3 30/60 + 2 57/60 + 4 45/60 =
9 132/60 = 1
1 12/60 =
11 1/5
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-Chetan K
