I would but I’m stuck on this problem too
2=-3(5)+b. First, you isolate the variable 2-3(5)=b. Then you solve 2-3(5)=2-15=-13. So -13=b
Answer:
366 cm^3
Step-by-step explanation:
V = lwh
1st rectangle (L) = 3 x 6 x 15 = 270 cm^3
2nd rectangle (R) = 6 x 4 x 4 = 96 cm^3
270 + 96 = <u>366 cm^3</u>
Hope this helps
Let s represent the length of any one side of the original square. The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.
The area of this rectangle is (s+9)(s-2) = 60 in^2.
This is a quadratic equation and can be solved using various methods. Let's rewrite this equation in standard form: s^2 + 7s - 18 = 60, or:
s^2 + 7s - 78 = 0. This factors as follows: (s+13)(s-6)=0, so that s = -13 and s= 6. Discard s = -13, since the side length cannot be negative. Then s = 6, and the area of the original square was 36 in^2.
<span>(x÷4)−10=2</span><span>
x/4= 12
x= 12*4
x= 48</span>