What is this answer plz tell me what it is!

Given a normal distribution with mu equals 100μ=100 and sigma equals 10 commaσ=10, complete parts (a) through (d). loading...

m_a_m_a [10]

I believe the parts are:

A. What is the probability that Upper X greater than 95X>95?

B. What is the probability that Upper X less than 75X<75?

C.What is the probability that Upper X less than 85X<85 and Upper X greater than 125X>125?

D. 95% of the values are between what two X-values (symmetrically distributed around the mean)?

Solution:

We use the equation for z score:

z = (X – μ) / σ

Then use the standard normal probability tables to locate for the value of P at indicated z score value.

A. Z = (95 – 100) / 10 = - 0.5

Using the tables, the probability at z = -0.5 using right tailed test is:

P = 0.6915

B. Z = (75 – 100) / 10 = - 2.5

Using the tables, the probability at z = -2.5 using left tailed test is:

P = 0.0062

C. Z = (85 – 100) / 10 = - 1.5

Using the tables, the probability at z = -2.5 using left tailed test is:

P = 0.0668

Z = (125 – 100) / 10 = 2.5

Using the tables, the probability at z = 2.5 using right tailed test is:

P = 0.0062

So the probability that 85<X and X>125 is:

P(total) = 0.0668 + 0.0062

P(total) = 0.073

D. P(left) = 0.025, Z = -1.96

P(right) = 0.975, Z = 1.96

The X’s are calculated using the formula:

X = σz + μ

At Z = -1.96

X = 10 (-1.96) + 100 = 80.4

At Z = 1.96

X = 10 (1.96) + 100 = 119.6

So 95% of the values are between 80.4 and 119.6 (80.4< X <119.6).

7 0

2 years ago

Please Help!!!!!!! No stupid answers

Snowcat [4.5K]

A. The ratio of the person's shadow to their height is 6:2 or 3:1, so the height of the shadow is 360/3 or 120 m.
B. The model car's length divided by the ratio to the real car, which is 8.5/0.8 = 10.625 cm long.

6 0

2 years ago

Read 2 more answers

A quadrilateral WXYZ contains wxy where measure of wxy=92 degrees. Once rotated 270° about the origin and translated 2 units up,

Marianna [84]

Answer:

C. 92 degrees

Step-by-step explanation:

Given that the $\angle{wxy}=$ 92° which is one of the angles of the quadrilateral WXYZ

The quadrilateral is first rotated by 270° about the origin and then translated 2 units up, the new position of the quadrilateral is W'X'Y'Z'.

The shape of the quadrilateral is remained unchanged due to rotation and translation, so all the angles of the final quadrilateral W'X'Y'Z' is the same as the angles of the given quadrilateral WXYZ.

So, $\angle{w'x'y'}= \angle{wxy}$