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sleet_krkn [62]
3 years ago
13

None of this makes sense

Mathematics
1 answer:
Elena L [17]3 years ago
7 0

The volume of the cone is:

V=Sb×h/3=(pi×r²)×h/3, where Sb is the area of the base (circle of radius r) and h is the height.

V=pi×r²×h/3=pi×1.5²×5/3=11.775in³

The closest indicated value is the first one, 11.78in³

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A picture is 46 cm by 32 cm. A scale diagram of the picture must fit in a space that is 3 m by 2 m. Which scale would be the mos
Marrrta [24]

Answer:

A picture that is 46cm by 32 cm must fit in a space that is 3m by 2m

First, let's rewrite both of these dimensions in the same units.

Knowing that:

1m = 100cm

Then the dimensions of the space can be rewritten from:

3m by 2m

to:

300cm by 200cm

So, if we enlarge our original picture by a scale factor K, the new dimensions of the picture will be:

K*46cm by K*32cm

Now we just need to find a value of K such that:

K*46cm is something near to 300cm

K*32cm is something near to 200cm

First, we can solve the equation:

K*46cm = 300cm

solving this for K we get:

K = 300cm/46cm = 6.5

While if we solve the equation:

K*32cm = 200cm

we get:

K = 200cm/32cm = 6.25

So we got two possible scale factors.

Which one we should take?

Notice that if we wanted to use the larger one (K = 6.5) for the 32cm side. the new length would be:

32cm*6.5 = 208cm

This is larger than the 200cm of space that we have

Then we can not select the larger option, we can only take the other value:

K = 6.25

Then we can conclude that a reasonable scale factor to use is K = 6.25

4 0
3 years ago
Last year. Samara practiced playing the violin for 26 hours the piano for 35 hours, the flute for 41 hours, and the drums for 18
vova2212 [387]

Answer:

5 days

Step-by-step explanation:

26+35+41+ 18 = 120

120/24 = 5

3 0
2 years ago
The ratio of the surface areas of two similar solids is 49:100. What is the ratio of their corresponding side lengths?
algol13
<span>ratio of surface area = 49:100
ratio of corresponding lengths = √49:√100 = 7:10
answer: C

Hope this helps


</span>
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