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kumpel [21]
3 years ago
11

For the high school's production of "Grease," 490 tickets were sold. The cost of a student

Mathematics
1 answer:
damaskus [11]3 years ago
3 0

<em><u>The system of equations could  be used to determine the number of each type of ticket sold is:</u></em>

s + p + t = 490

8s + 10p + 12t = 4600

s + p = 6t

<em><u>Number of each type of ticket sold is:</u></em>

number of student tickets sold = 220

number of pre-sale non student ticket sold = 200

number of ticket sold at door = 70

<em><u>Solution:</u></em>

Let "s" be the number of student tickets sold

Let "p" be the number of pre-sale non student ticket sold

Let "t" be the number of ticket sold at door

Cost of 1 student ticket = $ 8

Cost of 1 pre-sale non student ticket = $ 10

Cost of 1 ticket sold at door = $ 12

From given information,

<u><em>490 tickets were sold. So we can frame a equation as:</em></u>

number of student tickets sold + number of pre-sale non student ticket sold + number of ticket sold at door = 490

s + p + t = 490 ---------- eqn 1

<em><u>Also given that, The  total income from ticket sales was $4600</u></em>

So we can frame a equation as:

number of student tickets sold x Cost of 1 student ticket + number of pre-sale non student ticket sold x Cost of 1 pre-sale non student ticket + number of ticket sold at door x Cost of 1 ticket sold at door = $ 4600

s \times 8 + p \times 10 + t \times 12 = 4600

8s + 10p + 12t = 4600 ------ eqn 2

<em><u>The combined number of student and pre-sale  tickets was 6 times more than the tickets sold at the door</u></em>

s + p = 6t --------- eqn 3

So eqn 1 eqn 2 and eqn 3 could  be used to determine the number of each type of ticket sold

<em><u>Let us solve eqn 1, eqn 2, eqn 3 to find values of "s" "p" and "t"</u></em>

Substitute eqn 3 in eqn 1

6t + t = 490

7t = 490

<h3>t = 70</h3>

Substitute t = 70 in eqn 2

8s + 10p + 12(70) = 4600

8s + 10p = 3760 ----- eqn 4

Substitute t = 70 in eqn 3

s + p = 6(70)

s + p = 420  ----- eqn 5

Multiply eqn 5 by 8

8s + 8p = 3360  ----- eqn 6

Subtract eqn 6 from eqn 4

8s + 10p = 3760

8s + 8p = 3360

(-) ---------------------

2p = 400

<h3>p = 200</h3>

Substitute p = 200 in eqn 5

s + 200 = 420

<h3>s = 220</h3>

<em><u>Summarizing the results:</u></em>

number of student tickets sold = 220

number of pre-sale non student ticket sold = 200

number of ticket sold at door = 70

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