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dybincka [34]
3 years ago
6

Joey participated in a standardized reading test. He scored in the middle of the third stanine in a normal distribution. All of

the following are incorrect except:_________. a. His score was the median for the group that participated in the test.b. His t-score is 40.c. His score fell at +2 standard deviationd. His score fell at a z-score of -3.
Mathematics
1 answer:
GarryVolchara [31]3 years ago
4 0

Answer:

b. His t-score is 40.

Step-by-step explanation:

The middle of the third stanine in a normal distribution means that the standard of nine that is applied has the middle of the third count.

It means that if we divide the normal distribution with the standard of nine we will find the score to be  the middle of the  third division.

So it will be (1/3*9=3) more than 3.

Which in normal distribution will be more than 30.

The t distribution is approximately normal when the number of degrees of freedom is greater than 30 .

So the best answer is that <u>His t-score is 40 </u>  ( choice b).

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Answer:

As Per Provided Information

We have to use π = 3.14

Diameter of baseball is 3 inch

So, Radius of Baseball will be

  • Radius = Diameter/2

Radius = 3/2 inch

Radius = 1.5 inch

we have been asked to determine the surface area of given baseball .

<u>Using </u><u>Formulae </u>

<u>\boxed {\bf  \: Surface \:  Area_{(Baseball)} \:  = 4 \pi {r}^{2} }</u>

substituting the value and let's solve it

\longrightarrow\tt  \:Surface  \: Area_{(Baseball)} \:  = 4 \times 3.14 \times  {1.5}^{2}  \\  \\  \\ \longrightarrow\tt  \:Surface  \: Area_{(Baseball)} \:  = \: 4 \times 3.14 \times 2.25 \\  \\  \\ \longrightarrow\tt  \:Surface  \: Area_{(Baseball)} \:  = \: 12.56 \times 2.25 \\  \\  \\ \longrightarrow\tt  \:Surface  \: Area_{(Baseball)} \:  = \: 28.26 \:  {inch}^{2}

<u>Therefore</u><u>,</u>

  • <u>Surface</u><u> </u><u>Area </u><u>of</u><u> </u><u>baseball</u><u> </u><u>is </u><u>2</u><u>8</u><u>.</u><u>2</u><u>6</u><u> </u><u> </u><u>sq.</u><u> </u><u>inch</u><u> </u><u>.</u>

So, your answer is 28.26 sq.in

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