I THINK it’s the first or third
Problem:
The area of the patio of a relative's house is 20 square meters.
The width of the patio is 2 meters.
What is the length of the patio?
Solution:
The area is:
A = (w) * (l)
Where,
w: width
l: long
Clearing l we have:
l = A / w
Substituting values:
l = 20/2
l = 10 meters
Answer:
There are 3 terms
so it's answer A
Step-by-step explanation:
This is because terms are separated by + or - signs
A^2 + b^2 = c^2.....a and b are the legs and c is the hypotenuse
4^2 + b^2 = 5^2
16 + b^2 = 25
b^2 = 25 - 16
b^2 = 9
b = sq rt 9
b = 3 m
1 meter = 100 cm....so 3 meters = 3(100) = 300 cm
ur answer : the tree is 300 cm high
