Question

Given the function rule f(x)= x^-2 - 4x + 3, what is the output of f(-3)?

Answer 1

ax^2+bx+c
x^2-4x+3
(x-3)(x-1)=0
x=3, x=1 when y=0
The graph of the parabola has a minimum because a is positive.
(3+1)/2=2 so y will be at a minimum when x=2
f(x)=y=2^2-(4*2)+3
=4-8+3