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ankoles [38]
3 years ago
12

Two electronics students are discussing static electricity and electric current. Student A says that a basic property of static

electricity is the fact that it can't be detected. Student B says that an electric current results when electrons move in a conductor. Which of the following statements is correct? A. Neither of the two students is correct. B. Only Student A is correct. C. Both of the students are correct. D. Only Student B is correct.
Computers and Technology
1 answer:
Svet_ta [14]3 years ago
3 0
The answer is D. Only student B is correct. Student A is incorrect because static electricity can be detected through the principle of electrostatic induction, which will indicate if there are static electricity on the surface of an object. A device which can detect static electricity is an electroscope. Moreover, for student B, it is correct that the cause for electric current to flow is the uniform flow of free electrons.
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Margarita [4]

Answer:

Developers are people who build a website's core structure using coding languages, while designers are more visually creative and user-focused. Developers use their programming knowledge to breathe life into the designer’s creative vision.

You could think of developers as construction workers, and web designers as architects – both necessary, but different, skill sets.

I hope this helped :D

Explanation:

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3 years ago
Determine the exact output of the code $str = "The quick brown fox jumps over the the lazy dog"; echo strpos($str, 'fox');
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Answer:

b. 16

Explanation:

The given PHP code segment consists of 2 statements.

$str="The quick brown fox jumps over the lazy dog";

This defines a variable $str and assigns the given text to it.

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Gunther is filling in his own input mask. He wants to format the Social Security numbers of his clients. The field must contain
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Last one I am not sure they
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Consider two different implementations, M1 and M2, of the same instruction set. There are three classes of instructions (A, B, a
ANTONII [103]

Answer:

a) the average CPI for machine M1 = 1.6

the average CPI for machine M2 = 2.5

b) M1 implementation is faster.

c) the clock cycles required for both processors.52.6*10^6.

Explanation:

(a)

The average CPI for M1 = 0.6 x 1 + 0.3 x 2 + 0.1 x 4

= 1.6

The average CPI for M2 = 0.6 x 2 + 0.3 x 3 + 0.1 x 4

= 2.5

(b)

The average MIPS rate is calculated as: Clock Rate/ averageCPI x 10^6

Given 80MHz = 80 * 10^6

The average MIPS ratings for M1 = 80 x 10^6  / 1.6 x 10^6

= 50

Given 100MHz = 100 * 10^6

The average MIPS ratings for M2 = 100 x 10^6 / 2.5 x 10^6

= 40

c)

Machine M2 has a smaller MIPS rating

Changing instruction set A from 2 to 1

The CPI will be increased to 1.9 (1*.6+3*.3+4*.1)

and hence MIPS Rating will now be (100/1.9)*10^6 = 52.6*10^6.

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